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seropon [69]
3 years ago
11

the sum of two numbers is 9. if one number is subtracted from the other, the result is 3. find the numbers

Mathematics
2 answers:
LekaFEV [45]3 years ago
8 0
Let's say x to the first number and y to the second one.
We add them : x+y=9
Then we substract them : x-y=3
Now we add the equations: 

(x+y)+(x-y)=9+3\\ x+x+y-y=12\\ 2x=12\\ \\ x=\frac { 12 }{ 2 } \\ \\ x=6

and finally rewrite the equation:

6+y=9\\ y=9-6\\ y=3\\ \\ x=6\quad and\quad y=3
irakobra [83]3 years ago
6 0
X, y - the numbers

The sum of the two numbers is 9.
x+y=9

If one number is subtracted from the other, the result is 3.
x-y=3

Solve the system of equations:
x+y=9 \\
\underline{x-y=3} \\
x+x=9+3 \\
2x=12 \ \ \ |\div 2 \\
x=6 \\ \\
x+y=9 \\
6+y=9 \ \ \ |-6 \\
y=3

The numbers are 6 and 3.
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Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

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Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

M_d=M_1-M_2=53-41=12

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176

The degrees of freedom are:

df=n_1+n_2-1=36+49-2=83

The critical t-value for a 95% confidence interval and 83 degrees of fredom is t=1.989.

The margin of error (MOE) can be calculated as:

MOE=t \cdot s_{M_d}=1.989 \cdot 2.176=4.328

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 12-4.328=7.67\\\\UL=M_d+t \cdot s_{M_d} = 12+4.328=16.33

The 95% confidence interval for the difference of means is (7.67, 16.33).

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