Yes, I can do that using my pencil or my calculator.
1207838929299236636236+2892
Answer:
Step-by-step explanation:
, where b, h, w are base, height and width respectively.
, where h is the height, and A_b is the area of the base.
First let's calculate the volume of the paralelipiped by the first formula.

Then let's find out the height of the pyramid, which is 12 - 4 = 8 in.(See drawing)
Then the area of the base of the square pyramid is simply.

Now we can find the volume of the pyramid.

To find the total volume, let's add both volumes.

Answer:
Length of the rectangle = 9.58 feet and width = 27.14 foot
Step-by-step explanation:
Let the length of the rectangular area is = x feet
and the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 260
y =
-------(1)
Cost to fence the three sides = $3 per foot
Therefore cost to fence one length and two width of the rectangular area
= 3(x + 2y)
Similarly cost to fence the fourth side = $14 per foot
So, the cost of the remaining length = 14x
Total cost to fence = 3(x + 2y) + 14x
Cost (C) = 3(x + 2y) + 14x
C = 3x + 6y + 14x
= 17x + 6y
From equation (1)
C = 
Now we take the derivative,
C' = 17 - 
To minimize the cost of fencing,
C' = 0
17 -
= 0
= 17


x = 9.58 foot
and y =
y = 27.14 foot
Area of circle= πr² so, our radius would be 5in because the diameter is 10 in which makes our sum to be π×5²= 78.5 in
Circumference of circle= 2πr so, 2×5×π= 31.4 in