Answer:
x = 7
y = 11
z = 14
Step-by-step explanation:
x + y + z = 32
Let's say the youngest is x, middle is y and oldest is z.
y= x+4 (age of the youngest + 4)
z= 2x (twice as old)
We can replace y and z in the main equation above with these values that contain x.
x + (x + 4) + 2x = 32
4x = 28, divide both sides by 4
y = x + 4 = 7 + 4 = 11
z = 2x = 2*7 = 14
And to check: 7 + 11 + 14 = 32
Oldest=14
Middle=11
Youngest=7
Oldest is 2x youngest (7*2=14)
one you figure out the youngest (7) then *2 to get eldest(14)
32-7=25
25-14=11<--age of middle child that is 4 years older than youngest (7+4=11)
6 11/24
7 3/24 - 16/24
6 27/24 - 16/24
The answer is in the image below
-5x-36+8x
3x-36
3(x-18)
Dom(gof)=Dom(f)={1,3,4}.
(gof)(1)=g{f(1)}=g(2)=3.
(gof)(3)=g{f(3)}=g(5)=1.
(gof)(4)=g{f(4)}=g(1)=3.
∴gof={(1,3),(3,1),(4,3)}.
