The ages of three siblings total 32 years. The middle child is 4 years older than the youngest, and the eldest is twice as old a s the youngest. How old is each child?
2 answers:
Answer:
x = 7
y = 11
z = 14
Step-by-step explanation:
x + y + z = 32
Let's say the youngest is x, middle is y and oldest is z.
y= x+4 (age of the youngest + 4)
z= 2x (twice as old)
We can replace y and z in the main equation above with these values that contain x.
x + (x + 4) + 2x = 32
4x = 28, divide both sides by 4
x = 7
y = x + 4 = 7 + 4 = 11
z = 2x = 2*7 = 14
And to check: 7 + 11 + 14 = 32
Answer:
Oldest=14
Middle=11
Youngest=7
Step-by-step explanation:
Oldest is 2x youngest (7*2=14)
one you figure out the youngest (7) then *2 to get eldest(14)
32-7=25
25-14=11<--age of middle child that is 4 years older than youngest (7+4=11)
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