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MrRissso [65]
3 years ago
14

sam has 50 blue and 150 red marbles. She puts all of the marbles into bags equally. Each bag has one type of marble.Hom many mar

bles can she put in one bag?
Mathematics
2 answers:
NISA [10]3 years ago
8 0
I believe 50, since if it has to be equal, the largest common multiple (for this question that can make sense) to 50 and 150 is 50.
Mashutka [201]3 years ago
7 0
She can put 3 red marbles and 1 blue marbles in each bag. And there will be 50 bags and 4 marbles in each one.
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2, 16

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I'm reasking a previous question to make it more clear. This is a Linear Equation that I must solve. It includes fractions (the
Ugo [173]

Assuming the equation is:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)


When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.


Here the denominators are 2 and 10, hence the LCM is 10.


Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:

10\frac{x}{2}-10\frac{10x-25}{10}=10*3(x+3)-10(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

5x-(10x-25)=30(x+3)-10(x-14)

Now, distribute, i.e. remove parentheses and distribute:

5x-10x+25=30x+90-10x+140

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transpose terms

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In this particular case, we can also take advantage of the term

(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.

If we do that, the solution will be:

Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:

\frac{x}{2}-\frac{10x-25}{10}=3(x+3)-(x-14)

simplify, remember that there are always implied parentheses around numerators and denominators:

2\frac{x}{2}-2\frac{2x-5}{2}=2*3(x+3)-2(x-14)

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Now, distribute, i.e. remove parentheses and distribute:

x-2x+5=6x+18-2x+28

Simplify

-x+5=4x+46

solve

5-46=4x+x

-41=5x

x=-41/5

with the same results.

7 0
4 years ago
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Elena-2011 [213]
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