All categories

3 years ago

9=10 8=18 7=24 6=28 5=30 3=??

Mathematics

1 answer:

natima [27]3 years ago

7 0

Answer:

28.5

Step-by-step explanation:

This is because each number increases by half of the previous number,

the difference between 10 and 18 is eight, which when halved is 4,

the difference between 18 and 24 is four, the pattern then carries on...

Hopefully you found this useful :)

You might be interested in

When conducting a significance test in practice, how should you choose the alpha level?.

iVinArrow [24]

The alpha level should always be set to 0.05.

The supplied statement;

How should you select the alpha() level when doing a significance test in practice,

⇒ Use a higher alpha when the consequences of wrongly rejecting the null hypothesis are more severe. Select alpha () = 0.05 in every situation since it is the best option. Use a smaller alpha when the consequences of wrongly rejecting the null hypothesis are more severe.

To learn more about significance test click here:

brainly.com/question/12972662

#SPJ4

6 0

1 year ago

Help pls! I need help to finish :(<br> No Links!

atroni [7]

The answer is 7.5.
7 4/8 is also 7.5

5 0

2 years ago

Can a triangle be drawn with the following angle measures? Why or why not?<br> 50°, 70°, 70°

Viefleur [7K]

no, the 3 angles of a triangle need to equal 180 degrees

70 +70 +50 = 190 degrees so it cant be a triangle.

4 0

3 years ago

Read 2 more answers

If the average weight for cats is 12

Mariulka [41]

Answer:

3 standard deviations

from the mean is 6 pounds to 18 pounds.

Step-by-step explanation:

The above question is solved using empirical rule

99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

From the above question

μ = 12 pounds

σ = 2 pounds

Hence:.

3 standard deviations from the mean is calculated as

μ - 3σ

[12 - 3(2)] pounds

=( 12 - 6) pounds

= 6 pounds

μ + 3σ

[12 + 3(2)] pounds

=( 12 + 6) pounds

= 18 pounds

Hence,3 standard deviations

from the mean is 6 pounds to 18 pounds.

on:

5 0

3 years ago

A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.31 lb, the mean of all of the weight

a_sh-v [17]

Answer:

a) The difference is of 3.222 lbs.

b) 1.64 standard deviations.

c) Z = 1.64

d) Not significant, as the z-score of 1.64 is between -2 and 2.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of all of the weights is x=2.088 lb, and the standard deviation of the weights is s=1.968 lb.

This means that $\mu = 2.088, \sigma = 1.968$

a. What is the difference between the weight of 5.31 lb and the mean of the weights?

This is $X - \mu = 5.31 - 2.088 = 3.222$

The difference is of 3.222 lbs.

b. How many standard deviations is that [the difference found in part (a)]?

This is the z-score. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.31 - 2.088}{1.968}$

$Z = 1.64$

1.64 standard deviations.

c. Convert the weight of 5.31 lb to a z score.

Z = 1.64, as found above.

d. If we consider weights that convert to z scores between −2 and 2 to be neither significantly low nor significantly high, is the weight of 5.31 lb significant?

Not significant, as the z-score of 1.64 is between -2 and 2.

5 0

3 years ago