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professor190 [17]
3 years ago
14

1+(-2-5)^2+(14-17)×4 please answer

Mathematics
1 answer:
hjlf3 years ago
6 0
When you simplify the expression you get 38. Hope this helps.

Answer = 38.
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What do you think Ginsburg is saying<br> about a judge's role in the Supreme Court?
VLD [36.1K]

\huge\mathfrak\red{Answer}

Ruth Bader Ginsburg began her career as a justice where she left off as an advocate, fighting for women's rights. In 1996, Ginsburg wrote the majority opinion in United States v. Virginia, holding that qualified women could not be denied admission to Virginia Military Institute.

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4 0
3 years ago
How do how you cross cancel multiplying fractions
DENIUS [597]

It's easy once you spot the ones that can cross cancel!

Say we have the fractions 8/10 and 20/23. \frac{8}{10} \frac{20}{23} (it's easier to see on top of each other)

If you look diagonally , so 8 and 23 and 10 and 20, you can see that 10 and 20 have a common factor. So we divide it by the highest common factor to reduce those numbers, making it easier to multiply. 10 and 20 can become 1 and 2, dividing by 10. So now we are left with 8/1 and 2/23, and now we multiply normally going across so 16/23.

This works going both diagonals and simplifying both, but in that case it would be easier to try and simplify the fractions before cross multiplying them.

Basically: look for those diagonals and if they can be divided down by the highest common factor, go for it to make it easier to multiply normally afterwards.

Hope I helped!

5 0
3 years ago
✓<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B19%20%2B%20%20%5Csqrt%7B30%20%2B%20%20%5Csqrt%7B32%20%2B%20x%20%20%7D%20%7D%
Setler79 [48]

We'll have to repeatedly square both sides of the equation, in order to get rid of the square roots. Squaring a first time yields

19+\sqrt{30+\sqrt{32+x}}=25

Move the 19 to the right hand side:

\sqrt{30+\sqrt{32+x}}=6

And square again:

30+\sqrt{32+x}=36 \iff \sqrt{32+x}=6

Square one last time:

32+x=36 \iff x=36-32=4

Let's check the solutions: all these squaring might have created external solutions:

\sqrt{19+\sqrt{30+\sqrt{32+4}}}=\sqrt{19+\sqrt{30+6}}=\sqrt{19+6}=\sqrt{25}=5

So, x=4 is a feasible solution.

8 0
3 years ago
From greatest to least what are the measures of the first two angles with negative measure that are coterminal with an angle mea
masya89 [10]

Answer:

-610

-970

Step-by-step explanation:

-360-250=-610

-360-610=-970

4 0
2 years ago
Marco made 2 errors in solving the following inequality. Identify the mistakes and correctly solve.
seraphim [82]

Answer:

Step-by-step explanation:

When moving -18 to the other side, he didn’t do 20 + 18. (Mistake 1)

When dividing 2/-4 he didn’t flip the inequality from > to <. (Mistake 2)

Correct:

-18-4y

7 0
2 years ago
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