The percent increase in enrollment is 6 %
The operation used in first step is finding the difference between final value and initial value
<h3><u>Solution:</u></h3>
Given that This year, 1,272 students enrolled in night courses a a local college
Last year only 1,200 students enrolled.
To find: percent increase in the enrollment
The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.
<em><u>The percent increase is given as:</u></em>
Here initial value (last year) = 1200 and final value(this year) = 1272
Substituting the values in above formula,
Thus percent increase is 6 %
T=650mi(hr/50mi)=13 hr
t-1=12 hr
12=650/(50+v) multiply both sides by 50+v
600+12v=650 subtract 600 from both sides
12v=50 divide both sides by 12
v=25/6 mph
v≈4.17mph
9514 1404 393
Answer:
-361
Step-by-step explanation:
Your calculator can tell you the result. It is -361.
Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.
-3[2/6+8{-9/3(8-5*3)-6}]
= -3[2/6+8{-9/3(8-15)-6}]
= -3[2/6+8{-9/3(-7)-6}]
= -3[2/6+8{-3(-7)-6}]
= -3[2/6+8{21-6}]
= -3[2/6+8{15}]
= -3[1/3+8{15}]
= -3[1/3+120]
= -3[361/3]
= -361
Answer:
its c
Step-by-step explanation:
The first figure has 3 line segments.
the second figure has 3+3 =3*2 = 6 line segments
the third figure has 3+3+3 = 3*3 = 9 line segments
the fourth figure has 3+3+3+3=3*4=12 line segments...
so it is clear that:
the 20th figure has 3*20=60 line segments.
Answer: 60
