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3 years ago

How many right angles are formed when two perpendicular lines intersect?

Mathematics

2 answers:

kirza4 [7]3 years ago

6 0

Answer:

4 right angles at the intersection

Step-by-step explanation:

in total with the 2 perpendiculars that form 2 right angles at each in the initial point the total should probably be 8

posledela3 years ago

3 0

Two lines are perpendicular if and only if they form a right angle.

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The table shows the distance Allison drove one day of her vacation. Is the relationship between the distance and the time propor

miv72 [106K]

Answer:

hope that it helps you any

Step-by-step explanation:

first hour she drove 60mi

second hour she drove 50mi

third hour she drove 70mi

fourth hour she drove 20mi

fifth hour she drove 75mi

all together she drove 275miles

take 275 divide it by 5 you get an average of 55mph

7 0

2 years ago

According to a study conducted in one city, 35% of adults in the city have credit card debts more than $2.000. A simple random s

BabaBlast [244]

Answer:

Binomial; \mu p=87.5, \sigma p=7.542

Step-by-step explanation:

a distribution is said be a binomial distribution iff

The probability of success of that event( let it be p) is same for every trial
each trial should have 2 outcome : p or (1-p) i.e, success or failure only.
there are fixed number of trials (n)
the trials are independent

here, the trials are obviously independent ( because, one person's debt doesn't influence the other person's)

here n=250

the probability of success(0.35) is same for every trial

(35/100=0.35 is the required p here)

$\mu_{p} =n*p=250*\frac{35}{100} =250*0.35=87.5$

[since, the formula for $\mu _{p} =n*p$ ]

$\sigma _{p} =\sqrt{n*(p)*(1-p)} = \sqrt{250*0.35*(1-0.35)} = 7.542 ( approximately)$

[since, the formula for [tex]\sigma _{p} =\sqrt{n*(p)*(1-p)}

therefore, it is Binomial; \mu p=87.5, \sigma p=7.542

4 0

3 years ago

Divide. Reduce the answer to lowest terms.

Anastasy [175]

I don’t get the question

4 0

3 years ago

1.5 > 0.75x + 1 <br> what is x

motikmotik

Answer:

2/3 > x

Step-by-step explanation:

0.5 > 0.75x

2/3 > x

6 0

2 years ago

Three girls cut out decimal models of hundredths. Amber doesn't shade any of her models. Grace qualifies three fifths of a model

Varvara68 [4.7K]

Answer:

$Amber = 0$

$Grace = 0.60$

$Marsha =1.70$

Step-by-step explanation:

Given

<em>Decimal Grid = Hundredths</em>

$Amber = None$

$Grace = \frac{3}{5}th$

$Marsha = 1 + \frac{7}{10}th$

To solve for each:

We have:

For Amber:

$Amber = 0 * 100$

$Amber = 0$

For Grace:

$Grace = \frac{3}{5}th$

$Grace = \frac{3}{5} * 100$

$Grace = \frac{300}{5}$

$Grace = 60$

This means that Grace shaded 60 of the hundredth models.

Decimal shaded is:

$Grace = 60 * \frac{1}{100}$

$Grace =\frac{60}{100}$

$Grace = 0.60$

For Marsha:

$Marsha = 1 + \frac{7}{10}th$

$Marsha = \frac{10 + 7}{10}th$

$Marsha = \frac{17}{10}th$

$Marsha = 1.7th$

Multiply this by 100, to get the number of shaded

$Marsha = 1.7 * 100$

$Marsha = 170$

This means that Marsha shaded 170 of the hundredth models.

Decimal shaded is:

$Marsha = \frac{170}{100}$

$Marsha =1.70$

5 0

2 years ago