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3 years ago

Find the value of y when x = 4 in the equation 4x - 2 = y + 5 Show your work help

Mathematics

2 answers:

elena-s [515]3 years ago

5 0

First, substitute 4 into x
Then multiply 4 times 4
Subtract 2
Then subtract 5 from both sides

Basile [38]3 years ago

5 0

4(4)-2=y+5
16-2=y+5
14=y+5
9=y

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Jen has 6 yards of fabric and wants to make a new dress and shorts she used 3 1/3 yards of the fabric on her new dress how much

kodGreya [7K]

Answer:

$2\frac{2}{3}\ yards$

Step-by-step explanation:

we know that

To find out how much fabric Jen has left for the shorts, subtract the yards of fabric used in her new dress from the total yards of fabric Jen has.

$6-3\frac{1}{3}$

Convert mixed number to an improper fraction

$3\frac{1}{3}=\frac{3*3+1}{3}=\frac{10}{3}$

substitute

$6-3\frac{1}{3}=6-\frac{10}{3}=\frac{8}{3}\ yards$

Convert to mixed number

$\frac{8}{3}\ yards=\frac{6}{3}+\frac{2}{3}=2\frac{2}{3}\ yards$

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3 years ago

Help ASAP and explain why!!!

laila [671]

Answer:

c. Side-Angle-Side

Step-by-step explanation:

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3 years ago

Brainilest to who answers first

Sauron [17]

Answer: The exponential function would be

Step-by-step explanation:

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4 0

3 years ago

It says "find the measure of the angle indicated". The relationship is a same-side interior angle. I don't know how

weeeeeb [17]

180-50 would be 130.
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6 0

3 years ago

Can someone help me with this

SashulF [63]

Answer:

$\angle NRQ =85 \degree$

Given:

$\angle RPQ = 45 \degree \\ \angle PQR = (6x + 4)\degree \\ \angle NRQ = (15x - 5)\degree$

Step-by-step explanation:

Property used: An exterior angle of a triangle is equal to the sum of the opposite interior angles.

$= > \angle RPQ + \angle PQR = \angle NRQ \\ \\ = > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\ \\ = > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\ \\ = > 49\degree + 5 \degree= 15x\degree - 6x\degree \\ \\ = > 54\degree = 9x\degree \\ \\ = > 9x\degree = 54\degree \\ \\ = > x\degree = (\frac{54}{9} )\degree \\ \\ = > x\degree = 6\degree \\ \\ Putting \: value \: of \: x \: in \: \angle NRQ \\ \\ = > \angle NRQ = (15x - 5)\degree \\ \\ = > \angle NRQ = (15 \times 6 - 5) \degree \\ \\ = > \angle NRQ =85 \degree$

4 0

3 years ago