Find the value of y when x = 4 in the equation 4x - 2 = y + 5 Show your work help

Mathematics

2 answers:

elena-s [515]2 years ago

5 0

First, substitute 4 into x
Then multiply 4 times 4
Subtract 2
Then subtract 5 from both sides

Basile [38]2 years ago

5 0

4(4)-2=y+5
16-2=y+5
14=y+5
9=y

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Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial $4x^3+20x^2+2x-3$

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let $f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\$