Question

Quicklkkkkkkkk If a football player passes a football from 4 feet off the ground with an initial velocity of 36 feet per second, how long will it take the football to hit the ground? Use the equation h = −16t2 + 6t + 4. Round your answer to the nearest hundredth. 0.72 0.65 0.35 0.27

Answer 1

Answer:

Since time can't be negative, the only possible solution is 0.72 s.

Step-by-step explanation:

When the ball hits the ground its height is equal to 0, so we must find a value for "t" that results in h = 0. We have:

$-16*t^2 + 6*t + 4 = 0\\t_{1,2} = \frac{-6 \pm \sqrt{(6)^2 - 4*(-16)*(4)}}{2*(-16)}\\t_{1,2} = \frac{-6 \pm \sqrt{292}}{-32}\\t_{1,2} = \frac{-6 \pm 17.1}{-32}\\t_1 = \frac{-6 -17.1}{-32} = 0.72\\t_2 = \frac{-6 + 17.1}{-32} = -0.35$

Since time can't be negative, the only possible solution is 0.72 s.

Answer 2

Answer:

.72

Step-by-step explanation:

I got it right on the test!!!