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3 years ago

Perform the indicated operation. 1 3/4 · 7/3? a.3/4 b.41/12 c.121/12 d.23/4

Mathematics

1 answer:

castortr0y [4]3 years ago

6 0

Answer:

$\huge\boxed{b.\ 4\dfrac{1}{12}}$

Step-by-step explanation:

$1\dfrac{3}{4}\cdot\dfrac{7}{3}$

convert the mixed number to the improper fraction:

$1\dfrac{3}{4}=\dfrac{1\cdot4+3}{4}=\dfrac{7}{3}$

multiply:

$=\dfrac{7}{4}\cdot\dfrac{7}{3}=\dfrac{7\cdot7}{3\cdot4}=\dfrac{49}{12}=\dfrac{48+1}{12}=\dfrac{48}{12}+\dfrac{1}{12}=4\dfrac{1}{12}$

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110 and 294 are the outliers because their difference in value from other data is large.

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2 years ago

If m∠JKP=3r+12 and m∠2=4r−2, what is ∠JKN?

Leokris [45]

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3 years ago

Complete the equation: x^2+8x + _=(_)^2

pentagon [3]

Answer:

x^2+8x+16=(x-4)^2

EXPLANATION:

(a+b)^2=a2+2.a.b+b2

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3 years ago

Urgent please help!!

wolverine [178]

Answer:

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Step-by-step explanation:

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2 years ago

What are the solution(s) of x2-4-0?

Elanso [62]

Answer:

For $x^2 - 4 = 0$ , x = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

$x^2 - 4 = 0$

Now, using the ALGEBRAIC IDENTITY:

$a^2 - b^2 = (a-b)(a+b)$

Comparing this with the above expression, we get

$x^2 - 4 = 0 = x^2 - (2)^2 = 0\\\implies (x-2)(x+2) = 0$

⇒Either (x-2) = 0 , or ( x + 2) = 0

So, if ( x- 2) = 0 ⇒ x = 2

and if ( x + 2) = 0 ⇒ x = -2

Hence, for $x^2 - 4 = 0$ , x = 2, or x = - 2.

4 0

3 years ago

Read 2 more answers