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3 years ago

12

Why is brainly not working it say im logged out rn but im not i cant acces anything but this

Computers and Technology

2 answers:

solmaris [256]3 years ago

4 0

Answer:

Well, Basically it's your fault. It could be the Brainly Company because it happen to me. So, Good Luck!

$^{Itsbrazts}$

Grace [21]3 years ago

3 0

Answer:

the answers are unlimited now so you cant sigh up but if you cant log in then one of the things you filled i. Might be wrong

Explanation:

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A technician is buying a PC that will host three VMs running at the same time with the current configuration. The technician bel

raketka [301]

Answer:

B. SSD

Explanation:

VMs or virtual machines are virtually created environment for multiple operating system on a host operating system. The host operating system has an extension called Hyper-V. The hyper-V manager helps to manage the virtual machine's activities.

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3 years ago

What year was internet inverted

alex41 [277]

$\large\blue{\mid{\underline{\overline{\tt { →\:January \:1, 1983}\mid}}}}$

ARPANET→Advanced Research Projects Agency Network
the forerunner of the Internet.

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5 0

2 years ago

Which best describes a computer bug?

yanalaym [24]

Answer:

a piece of computer software containing defects that prevent a program from running properly

Explanation:

i got a 100% on the test

6 0

3 years ago

Question is attached as image, please help :>

harkovskaia [24]

Answer:

Proved

Explanation:

Given

$X = (a.\bar b)+(\bar a.b)$

$(a + b)\ .$ $\frac{}{a.b}$

Required

Find out why they represent the same

To do this, we simplify either $(a + b)\ .$ $\frac{}{a.b}$ or $X = (a.\bar b)+(\bar a.b)$

In this question, I will simplify $(a + b)\ .$ $\frac{}{a.b}$

Apply de morgan's law

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $(a + b) . (\bar a + \bar b)$

Apply distribution property

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $a.\bar a + a.\bar b + \bar a . b + b . \bar b$

To simplify, we apply the following rules:

$a.\bar a = 0$ --- Inverse law

$b.\bar b = 0$ --- Inverse law

So, the expression becomes

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $0 + a.\bar b + \bar a.b + 0$

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $a.\bar b + \bar a.b$

Rewrite as:

$(a + b)\ .$ $\frac{}{a.b}$ $=$ $(a.\bar b)+(\bar a.b)$

From the given parameters:

$X = (a.\bar b)+(\bar a.b)$

This implies that:

$(a + b)\ .$ $\frac{}{a.b}$ when simplified is X or $(a.\bar b)+(\bar a.b)$

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3 years ago

What is the maximum number of elements that will be visited by the binary search algorithm when searching a sorted 45-element ar

sergey [27]

The max nukber of elements visited will be 6.

6 0

2 years ago