Answer:
A and C
Explanation:
Option A:
In IPv6 there is a rule to reduce an IPv6 address when there are two or more consecutive segments of zeros just one time. This rule says that you can change the consecutive zeros for “::”
Here is an example
How to reduce the following IPv6 address?
ff02:0000:0000:0000:0000:0000:0000:d500
Ans: ff02::d500
Example 2:
2001:ed02:0000:0000:cf14:0000:0000:de95
Incorrect Answer -> 2001:ed02::cf14::de95
Since the rule says that you can apply “::” just one time, you need to do it for a per of zero segments, so the correct answer is:
Correct Answer -> 2001:ed02::cf14:0:0:de95
Or
2001:ed02:0:0:cf14::de95
Option C:
Since in IPv6 there are 
available addresses which means 340.282.366.920.938.463.463.374.607.431.768.211.456 (too many addresses), there is no need of NAT solution, so each device can have its own IP address by the same interface to have access through the internet if needed. If not, you can block the access through internet by the firewall.
Answer:
you select the element you wish to animate
Answer:
<em>Internet backbone</em>
Explanation:
The internet backbone is made up of multiple networks from multiple users. It is the central data route between interconnected computer networks and core routers of the Internet on the large scale. This backbone does not have a unique central control or policies, and is hosted by big government, research and academic institutes, commercial organisations etc. Although it is governed by the principle of settlement-free peering, in which providers privately negotiate interconnection agreements, moves have been made to ensure that no particular internet backbone provider grows too large as to dominate the backbone market.
Answer:
B and C
Explanation:
xPos and yPos determine the center of the circle, and rad determines the radius of the circle drawn.
It cannot be A because it starts drawing a circle with the center of (4, 1). None of the circles ahve a center at (4, 1). It is B because while it does start at (4, 1), the repeat function adds one to the y and radius. While ti repeats 3 times it ends up drawing all 3 circles. C also works because it starts by drawing the biggest circle and then subtracting the values to make the other two. It cannot be D because in the repeat function it subtracts from the y value and radius too early, it doesn't draw the biggest circle.
