Answer:
350 kHz
Explanation:
as there are 100,000 character per sec.
so, total number of bits per sec = 100,000 * n
= 100,000 * 7 = 700,000 bits per sec
= 700 kbps
Bandwidth (BW) = total no. of bits / 2
BW = 700 kbps/2
= 350 kHz
It's B. grammar errors are blue and autocorrect suggestions produce a small dialog box. I'm unsure what D is, but it's not an underline.
leave (i'm pretty sure this is the answer)
Answer:
#define LSH_RL_BUFSIZE 1024
char *lsh_read_line(void)
{
int bufsize = LSH_RL_BUFSIZE;
int position = 0;
char buffer = malloc(sizeof(char) bufsize);
int c;
if (!buffer) {
fprintf(stderr, "lsh: allocation error\n");
exit(EXIT_FAILURE);
}
while (1) {
// Read a character
c = getchar();
// If we hit EOF, replace it with a null character and return.
if (c == EOF || c == '\n') {
buffer[position] = '\0';
return buffer;
} else {
buffer[position] = c;
}
position++;
// If we have exceeded the buffer, reallocate.
if (position >= bufsize) {
bufsize += LSH_RL_BUFSIZE;
buffer = realloc(buffer, bufsize);
if (!buffer) {
fprintf(stderr, "lsh: allocation error\n");
exit(EXIT_FAILURE);
}
}
}
}
Explanation:
Option D is the answer.
Option A is rejected because in centralized communication notwork there is no free flow of communication in all directions ( all direction means between all the groups or layers of the network).
Option B is not the answer because centralized and decentralized networks has nothing to do with the size of organizations.
Option C is rejected because decision making process depends on the hard work and technical skills of groups of an organization about a field but not by the network discipline.
Option D is selected because in centralized network the information or decision making power is primarily limited to the upper level or higher members of organization and as mentioned decentralized decides on the basis of decision of all the groups or levels of the network.
