I will hope this helps :p
Explanation:
Let the size of a large server be L, and
the size of a small server be S.
We are given two scenarios,
2L+4S = 64.............(1)
and
L+3S = 40...............(2)
We solve the equations as follows
2(2)-(1)
2L-2L +6S-4S = 2*40-64
2S = 16
so S=8 ..................(3), size of small server
substitute (3) in (2)
L+3(8) =40
L = 40-24 = 16..............size of large server
Answer:
n! = n*(n-1)*(n-2)*(n-3)* ... *2*1
Explanation:
The factorial operator is simply a mathematical expression of the product of a stated integer and all integers below that number down to 1. Consider these following examples:
4! = 4 * 3 * 2 * 1
4! = 12 * 2 * 1
4! = 24
6! = 6 * 5 * 4 * 3 * 2 * 1
6! = 30 * 4 * 3 * 2 * 1
6! = 120 * 3 * 2 * 1
6! = 360 * 2 * 1
6! = 720
So, the factorial of n would follow the same as such:
n! = n * (n-1) * (n-2) * ... * 2 * 1
Cheers.
<span>Best Answer is
(D)</span>
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