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Blababa [14]
3 years ago
14

sqrt{20} \times 5 \sqrt{15} " alt=" - 3 \sqrt{20} \times 5 \sqrt{15} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Burka [1]3 years ago
8 0

(-3\sqrt{20} ) * (5\sqrt{15})\\  =-15\sqrt{300} \\ =-150\sqrt{3}

Hope this would help you .

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Read 2 more answers
Solve for c.<br> -c/2+43 = 50
noname [10]

\huge\text{Hey there!}

\mathsf{-\dfrac{c}{2}+43=50}

\large\text{SUBTRACT 43 to BOTH SIDES}

\mathsf{-\dfrac{c}{2}+43-43=50-43}

\large\textsf{CANCEL out: 43 - 43 because that gives you 0}

\large\textsf{KEEP: 50 - 43 because it helps solve for the c-value}

\mathsf{50 - 43 = \bf 7}

\large\text{NEW EQUATION: }\mathsf{-\dfrac{c}{2}=7}

\large\textsf{MULTIPLY }\mathsf{\dfrac{2}{-1}}\large\textsf{ to BOTH SIDES}

\mathsf{\dfrac{2}{-1}\times-\dfrac{c}{2}= \dfrac{2}{-1}\times7}

\large\textsf{CANCEL out: your RIGHT SIDE of the equation because that gives}\\\large\textsf{you 1}

\large\textsf{KEEP: }\mathsf{\dfrac{2}{-1}\times7}\large\textsf{ because that helps solve for the c-value}

\uparrow\large\text{SIMPLIFY THE EQUATION ABOVE \& YOU HAVE YOUR}\\\large\text{C-VALUE}\uparrow

\boxed{\boxed{\large\text{ANSWER: \huge\bf  c = -14}}}\huge\checkmark

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
What does a ka value of approximately 1 show about the equilibrium?
Crazy boy [7]
Some of the acid has dissociated

Hope this helps ;)
5 0
3 years ago
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