Answer:
Option B
Step-by-step explanation:
=> Cos 18
=> 0.9510
<u><em>To the hundredths place</em></u>
=> 0.95
Answer:
26
Step-by-step explanation:
Even integers will only have a square ending in 6 if they end in 4 or 6.
The square will only have a value greater than 76 if the number is greater than 8, that is, 14 or 16, 24 or 26, and so on.
The "smaller" integer will only be smaller if the "larger" integer is less than 16.
So, the two integers are ...
14 and (14^2 -76)/10 = 12
The sum of 14 and 12 is 26.
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In the graph, we let x represent the "larger" integer and y the "smaller". The shaded area is where x > y, and the curve is the constraint on their values. The two vertical lines are the even numbers whose squares end in 6, resulting in integer values for y.
Answer:
6.25 minutes or 375 seconds
Step-by-step explanation:
We can solve the following problem through the Proportion method.
Here,
we may take the time taken by the machine as x

Answer:
x = -5
Step-by-step explanation:
The equation y = x^2+10x+25 can be factored to (x+5)^2
when (x+5)^2 = 0
x = -5
meaning the equation has a line of symmetry at x = -5
Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.