Hello!
Here a graph of the slope!
Answer:
The first rocket, g(x), reached its maximum height before the second rocket, h(x).
Step-by-step explanation:
Each equation is in vertex form, so we can read the vertex of the rocket's path from the equation.
y = a(x -h)^2 +k . . . . . . has vertex (h, k)
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g(x) has vertex (time, max height) = (4, 170).
h(x) has vertex (time, max height) = (5, 170).
The rockets have the same maximum height (170), but the first rocket, g(x), reaches that height in 4 seconds, one second sooner than the second rocket, h(x).
The first rocket, g(x), reached its maximum height before the second rocket, h(x).
A. The ratio of soccer balls to all balls are 4:25
All the balls combined are 50 balls
8 of the balls are soccer balls so that makes the ration 8:50
In the simplest form it is 4:25 since you can't divide 4 or 8 by 50, you can use 2
and you get 4:25 as your answer
So it is A.
C(x)=rx+s we are told that x=3, c(x)=21, and s=3
21=3r+3 divide both sides by 3
7=r+1 subtract 1 from both sides
6=r so now c(x) becomes:
c(x)=6x+3
Hi again :)
(3p +2)(5p-1)
Distribute '
(3p)(5p)+(3p)(-1)+(2p=)(5p)+(2)(-1)
15p² - 3p + 10x - 2
15p² + 7p - 2
Thus, the correct option is : C
(5w+2)(8w+5) It says to use the tab, but I don't know :) so I am using my way :)
Distribute
(5w)(8w)+(5w)(5)+(2)(8w)+(2)(5)
40w² + 25w + 16w + 10
40w² + 41w + 10
Thus, The answer is B
Again, I don't know how to solve it by suing the tab. However, I will use my way :)
(-5y+3)(2y+5)
Distribute
(-5y)(2y)+(-5y)(5)+(3)(2y)+(3)(5)
-10y² - 25y + 6y + 15
-10y² - 19y + 15
Thus, the answer is : D
(6x - 5)(2x - 3)
Distribute
(6x)(2x)+(6x)(-3)+(-5)(2x)+(-5)(-3)
12x² - 18x - 10x + 15
12x² - 28x + 15
The answer is : A
For #12 The answer is : C
Now let's solve #13
(4x -6y³)²
Distribute
(4x)(4x)+(4x)(-6y³)+(-6y³)(4x)+(-6y³)(-6y³)
16x² - 24xy³-24xy³+36y^6
36y^6 - 48xy³ = 16x²
The answer is B
wow, that was a lot of work. Good luck!
