But actually its based on your luck
25 because there's 5 people so you take 5 times 5
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer:
Step-by-step explanation:
Given that According to a video streaming service, 48% of American couples are "cheaters", that is—they promise each other to watch a filmtogether, but one of them first watches it alone.
Here if this is binomial with two outcomes we can easily say that the other 52% couples go together movies.
But here there are not only two outcomes.
The other possibilities are:
i) Either both do not go to movies
ii) Both cheat and go to movies separately
Thus since there are not exactly two outcomes, we cannot say the other 52% go to movies together.
As much as say that 52% of couples are not cheating in this way.
