Answer:
no and yes
Step-by-step explanation:
no to the ,The Night of the spadefoot toad but yes to hatchet to be honest I think everyone read hatchet when they were in 5th grade cuz I know I did and it was pretty good oh yeah who have read the lion,witch and the wardrobe in fifth grade??
Let "a" and "b" represent the values of the first and second purchases, respectively.
0.40*(original price of "a") = $10
(original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
a = $25.00 -10.00 = $15.00
At the other store,
$29 = 0.58b
$29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate
Then Julia's total spending is
a + b = $15.00 +50.00 = $65.00
Julia spent $65 in all at the two stores.
Answer:
9π or 28.27 cm
Step-by-step explanation:
The circumference formula is 2πr or dπ. The diameter is 9 cm so we multiply 9 with pi to get the answer.
Answer:

Step-by-step explanation:
Given functions are:

We have to find:
(s.t)(x) => this means we have to multiply the two functions to get the result.
So,

Also we have to find
(s-t)(x) => we have to subtract function t from function s

Also we have to find,
(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

Putting x = -3

Hence,

Answer:
![f^{-1}(x)=\sqrt[3]{x}-6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-6)
Step-by-step explanation:



![\sqrt[3]{x}=y+6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B6)
![\sqrt[3]{x}-6=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D-6%3Dy)