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Tanzania [10]
3 years ago
14

Find a degree 3 polynomial with real coefficients having zeros 2 and 3i and a lead coefficient of 1. Write P in expanded form. B

e sure to write the full equation including
P(x)=​
Mathematics
1 answer:
Natali [406]3 years ago
7 0

Answer:

f(x)=x³-2x²+9x-18

Step-by-step explanation:

complex zeros always occur in pairs.

zeros are 2,3i,-3i

f(x)=(x-2)(x-3i)(x+3i)=(x-2)((x)^2-(3i)^2)

=(x-2)(x^2-9i^2)

=(x-2)(x^2+9)

=x^3-2x^2+9x-18

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kirill [66]

Answer:

x = 3 and y = 2

or

(3,2)

Step-by-step explanation:

first equation (LCM = 3 x 4 x 5 = 60)

(x+2)/5 - (9-x)/3 = (y - 6)/4

12(x+2) - 20(9-x) = 15(y - 6)

12x + 24 - 180 + 20x = 15y - 90

32x - 15y = -90 - 24 + 180

32x - 15y = 66

second equation:

8(x + 2) - (2x + y) = 2(x + 13)

8x + 16 - 2x - y = 2x + 26

6x - y + 16 = 2x + 26

4x - y = 10

Now you have 2 equations:

4x - y = 10  ---> y = 4x - 10

32x - 15y = 66

Substitute   y = 4x - 10 into 32x - 15y = 66

32x - 15(4x - 10) = 66

32x - 60x + 150 = 66

-28x = -84

    x = 3

    y = 4(3) - 10

    y = 12 - 10

    y = 2

Solutions: x = 3 and y = 2

6 0
2 years ago
Someone lmk what the answer is
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3 years ago
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Hope this helps :)

4 0
2 years ago
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