Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
Answer: 2/6 or 1/3
Step-by-step explanation: First you want to change the two fractions to improper fractions, so 2 1/6 will become 13/6 and 1 5/6 will become 11/6.
Using those improper fractions, you subtract the numerators since the denominators are the same, so 13 - 11 is 2 for the numberator.
2/6 can be simplified into 1/3 by dividing the numerator and denominator by 2.
(if 2 is a square)
6xy ( x2 - xy + y2)
= 6x3y - 6x2y2 - 6xy3 --------------the threes and twos on this line are squares and cubics. the six is just a whole number
it is a rational number (intergers are plus and minus whole numbers)
Answer:
jay caught 42 fish that more than blair
Step-by-step explanation:
