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3 years ago

Geometry question, someone pleaseeeee help me with it!!!

Mathematics

2 answers:

Taya2010 [7]3 years ago

6 0

Answer:

The coordinate of N is (-7,4)

Step-by-step explanation:

MN + NP = MP

We know that MN is 4/9 of MP

First we will look at the x distance

That total x distance is

-19 to 8 or 27 units

4/9 of 27 is 12

Add this to coordinate of M

Add 12 to -19 = -7

Now we will look at the y distance

12 to -6 or 18 units

18 * 4/9 = 8

Subtract this from coordinate of M since we are going down

12 -8 =4

The coordinate of N is (-7,4)

Vikentia [17]3 years ago

5 0

Answer:

(-7,4)

Step-by-step explanation:

MN is 4/9 NP so

To find the x value

-19 and 8 are 27 apart and 27(4/9)=12

so you add 12 to the x value of P so 12+-19=-7 so the x value of N is -7

so the same for the y value

12 and -6 are 18 apart

18(4/9)=8 so you subtract 8 from the y value of P

12-8=4

so the y value N is 4

so N is

(-7,4)

These 3 problem I have answered have been almost the same except the numbers do you not understand how to do these problems and if not I can help you understand for the last question?

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A box in a certain supply room contains four 40w, five 60w, and six 75w light-bulbs. suppose that three bulbs are randomly selec

weeeeeb [17]

Situation satisfies the criteria for the use of hypergeometric distribution. Since no replacement is made, binomial distribution is not applicable (probability does not remain constant).

A=number of target wattage bulbs
B=number of non-targeted wattage bulbs
a=number of target wattage bulbs selected
b=number of non-targeted wattage bulbs selected

P(a,b)=C(A,a)*C(B,b)/C(A+B,a+b)
where C(n,x)=combination of x items chosen from n=n!/(x!(n-x)!)

For all following problems,
A+B=4+5+6=15
a+b=3 (selected)

(a) Target wattage = 75W
A=6, B=9, a=2, b=1
P(a,b,A,B)
=P(2,1,6,9)
=C(6,2)*C(9,1)/C(15,3)
=15*9/455
=27/91

(b) target wattage = each of the three
Probability = sum of probabilities of choosing 3 40,60,75-watt bulbs
P(3x40W)+P(3x60W)+P(3x75W)
Case (A,B,a,b)
3x40W (4,11,3,0)
3x60W (5,10,3,0)
3x75W(6,9,3,0)

P(3x40W)+P(3x60W)+P(3x75W)
=C(4,3)*C(11,0)/C(15,3)+C(5,3)*C(10,0)/C(15,3)+C(6,3)*C(9,0)/C(15,3)
=4*1/455+10*1/455+20*1/455
=34/455

Can also be solved by elementary counting, for example, for (a),
P(2x75W)
=C(3,2)*6/15*5/14*9/13
=(3)*6/15*5/14*9/13
=27/91 as before

8 0

3 years ago

Hello! I'm having a problem figuring out this problem: 6c-9d=111 5c-9d=103

avanturin [10]

Answer:

C=8

Step-by-step explanation:

6c-9d=111

-) 5c-9d=103

6c-5c=c

-9c+9c=0

111-103=8

(Negative+Negative=Positive)

C=8

I need Brainliest!

8 0

3 years ago

Given the expression 12 over 12 to the third power.

4vir4ik [10]

Part 1:
Before we begin, you need to remember the following rule:
$\frac{x^a}{x^b} = x^{a-b}$

The given expression is:
$\frac{12}{12^3}$

Since the base is the same in both numerator and denominator, we can apply the above rule. This means that:
$\frac{12}{12^3}$ = 12¹⁻³ = 12⁻²

Part 2:
Before we begin, you need to remember the following rule:
x⁻ᵃ = $\frac{1}{x^a}$

Now, from part 1, we simplified the expression into 12⁻²
Since the power is negative, we can apply the above rule.
This means that:
12⁻² = $\frac{1}{(12)^2} = \frac{1}{12*12} = \frac{1}{144}$

Hope this helps :)

5 0

3 years ago

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In the following figure, m∠A = 55° and the m∠ACE = 86° . What is the m∠E = ? Show your work.

Paladinen [302]

the answer is

<E=31°.............. ..