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3 years ago

12

Jack has 2 3/4 ups of meat to fill for patties. If he uses 3/16 cups of meat for each patty, how many whole patties can jack mak

e?

1 answer:

zaharov [31]3 years ago

7 0

Answer:

14 2/3 is the asnwer

Step-by-step explanation:

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Plssss answer! Your team is renting a photo booth for the 8th grade dance, but you have to buy the photo paper and other supplie

Rama09 [41]

Answer:

$215.25

Step-by-step explanation:

4 0

3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

3 years ago

Billy went on the Yahoo Finance website to check the value of his investment. Yesterday his stock was worth

maxonik [38]

Answer:

The investment decreased by 16.5771% per share.

Step-by-step explanation:

7 0

3 years ago

Please help it's for a test!

Tanya [424]

Answer:

0.2322 or 23.22 %

Step-by-step explanation:

We have to solve and find the area out of these limits

μ + 0,3 = 210 + 0,3 ⇒ 210,3 and

μ - 0,3 = 210 - 0,3 ⇒ 209.7

z(l) = ( x - 210 ) / (2.8/√84) ⇒ z(l) = - (0.3 * 9,17)/ 2.8

z (l) = - 1.195

We need to interpole from z table

1.19 ⇒ 0.1170

1.20 ⇒ 0.1151

Δ ⇒ 0.01 ⇒ 0.0019

And between our point 1,195 and 1,19 the difference is 0.005

then 0.01 ⇒ 0.0019

0.005 ⇒ ?? (x)

we find x = 0.00095

to get the area for poin z (l) - 1.195 up to final left tail is from z table

0,1170 - 0.00095 = 0.1161

And by symmetry to the right is the same

So 0.1161 * 2 = 0.2322

We find the area out of the above indicated limits the area we were looking for. This is the probability of finding shafts over and below the population mean and 0.3 inches

Step-by-step explanation:

5 0

2 years ago

Triangle XYZ is shown on the coordinate grid

pav-90 [236]

Answer:

1,2,5

Step-by-step explanation:

7 0

3 years ago