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Leni [432]
3 years ago
12

Jack has 2 3/4 ups of meat to fill for patties. If he uses 3/16 cups of meat for each patty, how many whole patties can jack mak

e?
Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

14 2/3 is the asnwer

Step-by-step explanation:

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Which number is greater?<br><br> A. 3.33 x 10^7<br> B. 2.34 x 10^5
Zina [86]

Answer:

3.33times 10^7 because when it is possible to substract 2.24times10^5 from it

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Which equation can be used to solve for x in the following diagram?
Kruka [31]

Answer:

I'm answering this for points

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3 years ago
F(n+1)=f(n)-3 f(1)=15
Trava [24]

Answer:

f(n+1) = 13

Step-by-step explanation:

  • We know that f(1) = 15
  • So we can substitute this for f(n)-3
  • With this:
  1. f(n+1) = f(1) -3
  2. f(n+1) = 15-2
  3. f(n+1) = 13
5 0
3 years ago
If profit is p% and cost price is C.P what will be the selling price?​
harkovskaia [24]

Answer:

SP = (1+P/100)CP.

Step-by-step explanation:

P% is our profit on our cost price.

Cp is our cost price.

We know,

Selling Price - Cost price = Profit = Profit * Cost Price

So,

SP = (1+P/100)CP.

7 0
2 years ago
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
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