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lisov135 [29]
3 years ago
14

DEF is a dilation image of ABC. What is the scale factor?

Mathematics
2 answers:
lbvjy [14]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

MrRa [10]3 years ago
5 0
I believe it would be 2
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Find the area of the composite shape below.<br> help to get sum coin
enot [183]

Answer:

Composite Area = 1105.94

Step-by-step explanation:

Remark

The two semi circles at each end make an entire circle with radius 11. The width of the central rectangle = the diameter of the circle. The area should be able to be found.

Width

2*radius = width

width = 2 * 11

width = 22

Area of the circle

Area = pi * r^2

r = 11

Area = 3.14 * 11^2

Area = 3.14 * 121

Area = 379.94

Area of the rectangle

Area = L * W

L = 33

W = 22

Area = 33 * 22

Area = 726

Total Area

Total Area = Area of Rectangle + Area of the Circle

Total Area = 726 + 379.94 = 1105.94

3 0
3 years ago
according to the line plot what is the total weight gained by the dogs that gained 1/8 of a pound or 3/4 of a pound
omeli [17]

Answer:

i think the answer is 3

Step-by-step explanation:

8 0
2 years ago
How do i do this......
andrew11 [14]

Answer:

b is correct answer

Step-by-step explanation:

hope it helped

5 0
3 years ago
Please help!!!! I'll make you Brainliest!! Thanks!!
alexandr1967 [171]
Im thinking it whould be c
6 0
3 years ago
The travel-to-work time for residents in Ventura County is unknown. Assume the population variance is 39. How large should a sam
katen-ka-za [31]

Answer:

A sample size of 128 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.93}{2} = 0.035

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.035 = 0.965, so z = 1.81

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large should a sample be if the margin of error is 1 minute for a 93% confidence interval

We need a sample size of n, which is found when M = 1. We have that \sigma = \sqrt{39}. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.81*\frac{\sqrt{39}}{\sqrt{n}}

\sqrt{n} = 1.81\sqrt{39}

(\sqrt{n})^2 = (1.81\sqrt{39})^2

n = 127.8

Rounding up

A sample size of 128 is needed.

7 0
3 years ago
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