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3 years ago

DEF is a dilation image of ABC. What is the scale factor?

Mathematics

2 answers:

lbvjy [14]3 years ago

8 0

Answer:

1/2

Step-by-step explanation:

MrRa [10]3 years ago

5 0

I believe it would be 2

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Roger will flip a coin 3 times. which 2 events are disjoint?

lorasvet [3.4K]

The two events that are disjoint or mutually exclusive is getting a head and a tail at the same time. It because if you are going to flip a coin the result can either be head or tail but not both. The value of the two events occurring at the same is 0.

5 0

3 years ago

Nellie and her younger sister Debbie share expenses on a holiday. Nellie spends $122 more than Debbie. Their total expenses amou

VMariaS [17]

Answer:

see below

Step-by-step explanation:

Let N = how much Nellie spends

Let D = how much Debbie spends

Part A

Nellie spends $122 more than Debbie.

N= D +122

Their total expenses amount to $840.

N+D =840

The two equations are

N= D +122

N+D =840

Part B

We can substitute the first equation which is solved for N into the second equation. Every place we see an N in the second equation, we replace it with D+122

Part C

N= D +122

N+D =840

(D+122) +D = 840

Combine like terms

2D +122 = 840

Subtract 122 from each side

2D+122-122=840-122

2D =718

Divide by 2

2D/2= 718/2

D =359

Debbie spends 359

7 0

3 years ago

What is the slope of the line in the graph?

Artist 52 [7]

Answer:

is 1/1 a option? like one over one, as in a fraction....?

Step-by-step explanation:

8 0

3 years ago

If A = (7,9) and B = (3 , 12) what is the length of AB

V125BC [204]

Answer:

AB = 5 units

Step-by-step explanation:

Calculate the length using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+ (y_{2}-y_{1})^2$

with (x₁, y₁ ) = A(7, 9) and (x₂, y₂ ) = B(3, 12)

AB = $\sqrt{(3-7)^2+(12-9)^2}$

= $\sqrt{(-4)^2+3^2}$

= $\sqrt{16+9}$

= $\sqrt{25}$

= 5

7 0

2 years ago

Given the relationship x2 + 3y2 =12, with y > 0 and dx, dt = 2 units/min., find the value of dy, dt at the instant y = 1 unit

matrenka [14]

$\bf x^2+3y^2=12\implies \stackrel{chain~rule}{2x\cfrac{dx}{dt}}+3 \stackrel{chain~rule}{\left(2y\cfrac{dy}{dt}\right)}=0
\\\\\\
2x\cfrac{dx}{dt}+6y\cfrac{dy}{dt}=0
\implies 
6y\cfrac{dy}{dt}=-2x\cfrac{dx}{dt}\implies \cfrac{dy}{dt}=\cfrac{-2x\frac{dx}{dt}}{
6y\frac{dy}{dt}}
\\\\\\
\boxed{\cfrac{dy}{dt}=-\cfrac{x\frac{dx}{dt}}{3y}}\\\\
-------------------------------$

$\bf \textit{now, when y = 1, what is \underline{x}?}\qquad x^2+3y^2=12\implies x^2+3(1)^2=12
\\\\\\
x^2=9\implies x=\sqrt{9}\implies x=3\\\\
-------------------------------\\\\
\begin{cases}
y=1\\
x=3\\
\frac{dx}{dt}=2
\end{cases}\implies \cfrac{dy}{dt}=-\cfrac{3\cdot 2}{3\cdot 1}\implies \cfrac{dy}{dt}=-2$

7 0

3 years ago