Answer:
0.9792
Step-by-step explanation:
Data provided in the question:
Average gross sales = $1,240
Standard deviation = $180
sample size = 40
Now,
standard deviation of sample average
=
=
= 28.46
Now,
z value for 1200 =
= -1.4,
and,
p value for (z = -1.4) = 0.0808
therefore,
P(average < $1200) = 0.0808
Thus,
probability that the average over the next 40 weekdays will exceed $1,200
= 1 - 0.808
= 0.9792
Answer:
a is option c
b is 17.5
c is 9
Step-by-step explanation:
I do not know if all of these are right
Hi rainy here !!! so lets see lets set up your problem like this
X/1280 = 60%/100 so lets cross multiply
100 times X =100X
60 times 1280 = 76800
100X=76800 now lets divide each side by 100
100 divided by 100 = 0
76800 divided by 100 = 768
X=768
So now we have to subtract to get the total amount so 1280 minus 768 = 512
512 is your answer :)
Hope I helped if u have any questions on how I did your problem feel free to message me or comment on my page bye !!!
Love ~Rainy~