H1 (t) = 196 - 16 t-squared. / / / H2 (t) = 271-16t-squared. / / / In each function, 't' is the number of seconds after that ball is dropped. / / / Each function is only true until the first time that H=0, that is, until the first bounce. Each function becomes very complicated after that, and we would need more information in order to write it.
Take ln to both sides
ln 14^x = ln 5
then you'll get
x ln 14 = ln 5
divide both sides by ln 14
x = 0.6098533345
after rounding
x = 0.6099
The solution to the system of equations is x = 3 and y = 10
<h3>How to solve the equations?</h3>
The system is given as:
2x-2y=-14
3x-y=-1
Multiply (1) by 1 and (2) by 2
So, we have:
1(2x-2y=-14)
2(3x-y=-1 )
This gives
2x - 2y=-14
6x - 2y=-2
Subtract the equations
-4x = -12
Divide by -4
x = 3
Substitute x = 3 in 3x-y=-1
3(3)-y=-1
Evaluate
9 - y = -1
Solve for y
y = 10
Hence, the solution to the system of equations is x = 3 and y = 10
Read more about system of equations at:
brainly.com/question/12895249
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