Answer:
Iron is being oxidized at the anode and water is acting as the electrolyte.
Explanation:
When iron is exposed to oxygen and water , the rusting of iron takes place.
<u>The reaction taking place at anode : Oxidation of iron.</u>
The reaction taking place at cathode : Reduction of oxygen in the air.
The overall reaction:
The rust that is hydrated iron(III) oxide can form iron(II) ions which can react further with oxygen.
Thus, from the above reactions ,
Iron is being oxidized at the anode and water is acting as the electrolyte.
Ion with a 1+ charge. The atom would normally be neutral, since it has the same number of electrons as it does protons; removing an electron leaves one more proton than electron. Since protons are positive and there's one more of them than electrons in the new ion, it has a 1+ charge.
Answer:
38825.472 M
Explanation:
Using
C1V1=C2V2
To make solution B,
C1 = 25.527 M, V1 = 13 mL
C2 = 25.527 x 8 = 204.216 M
V2 = 13 X 12 = 156 mL
To make solution C'
C1 = 8 X 202.216 M = 1617.728
V1 = 8 X 156mL = 1248 mL
V2 = 4 X 13 = 52 mL
C2 = C1V1 / V2
=1617.728 X 1248 / 52
=38825.472 M
I think it will be D or B but my mine answer is D
