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Colt1911 [192]
2 years ago
8

For the balanced equation: 2H2S + 3O2 → 2SO2 + 2H2O

Chemistry
1 answer:
Irina-Kira [14]2 years ago
6 0

Answer:

8 moles SO₂

Explanation:

To find the moles SO₂, you need to multiply the given value by the mole-to-mole ratio. This ratio, between O₂ and SO₂, is made up of the coefficients from the balanced equation.

2 H₂S + 3 O₂ -----> 2 SO₂ + 2 H₂O

12 moles O₂          2 moles SO₂
--------------------  x  ----------------------  =  8 moles SO₂
                               3 moles O₂

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the boiling point of water is 212°F

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Identify each of the following compounds as: (a) a nonelectrolyte: lactose (c12h22o11) potassium chloride (kcl) lactic acid (hc3
11Alexandr11 [23.1K]

Nonelectrolytes are compounds that do not tend to get ionize in all solution. As a result, solutions which contains nonelectrolytes will not conduct electricity.

Ionic compounds dissolve in water and break into the constituent ions through the process called ionization. Now These electrolyte solutions can either be acids, or bases, or salts.

If  the process of ionization produces a large no. of ions in the solution, it is a strong electrolyte. On the other hand, if it produces only a few ions, the solution is a weak electrolyte,

Potassium chloride (KCL) is a strong electrolyte,

Lactic acid (HC3H503) is a weak electrolyte,

Whereas, Ethanol (C3H7OH) is a non electrolyte,

Dimethylamine (CH3)2NH is a weak electrolyte,

Sodium hydroxide(NaOH) is a strong electrolyte.

To learn more about nonelectrolytes, head here

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6 0
2 years ago
True or False: The particles in the GASEOUS state are the furthest apart
tatyana61 [14]
The answer is true, particles in the gaseous state are the furthest apart
4 0
3 years ago
Initially, 0.65 mol of PCl5 is placed in a 1.0 L flask. At equilibrium, there is 0.15 mol of PCl3 in the flask. What is the equi
borishaifa [10]

Answer : The equilibrium concentration of PCl_5 is, 0.50 M

Explanation : Given,

Initial moles of PCl_5 = 0.65 mole

Volume of solution = 1.0 L

Moles of PCl_3 at equilibrium = 0.15 mole

The balanced equilibrium reaction will be,

                          PCl_5\rightleftharpoons PCl_3+Cl_2

Initial moles     0.65        0         0

At eqm.           (0.65-x)     x         x

Moles of PCl_3 at equilibrium = x = 0.15 mole

Moles of Cl_2 at equilibrium = x = 0.15 mole

Moles of PCl_5 at equilibrium = (0.65-x) = (0.65-0.15) = 0.50 mole

Now we have to calculate the concentration of PCl_3,Cl_2\text{ and }PCl_5 at equilibrium.

Formula used : Concentration=\frac{Moles}{Volume}

\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}=\frac{0.15mole}{1.0L}=0.15M

\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}=\frac{0.15mole}{1.0L}=0.15M

\text{Concentration of }PCl_5=\frac{\text{Moles of }PCl_5}{\text{Volume of solution}}=\frac{0.50mole}{1.0L}=0.50M

Therefore, the equilibrium concentration of PCl_5 is, 0.50 M

8 0
4 years ago
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