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3 years ago

An aqueous solution is made by dissolving 26.4 grams of barium sulfide in 349 grams of water.

Chemistry

1 answer:

lukranit [14]3 years ago

4 0

Answer:

Molality = 0.43 m

Explanation:

Given data:

Mass of barium sulfide = 25.4 g

Mass of water = 349 g (349 g/1000 = 0.349 Kg)

Molality of water = ?

Solution:

Number of moles of barium sulfide:

Number of moles = mass/molar mass

Number of moles = 25.4 g/169.39 g/mol

Number of moles = 0.15 mol

Molality:

Molality = number of moles o f solute/ Kg of solvent

Molality = 0.15 mol / 0.349 Kg

Molality = 0.43 m

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<h3>Data obtained from the question </h3>

Molarity of stock solution (M₁) = 15 M
Volume of stock solution (V₁) = 500 mL
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