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arsen [322]
3 years ago
10

The product of two consecutive positive integers is 18 more than eight times the smaller number. Find the two numbers.

Mathematics
1 answer:
olga2289 [7]3 years ago
6 0

Let , smallest integer is x.

So , other one is x + 1.

By , given conditions :

x( x + 1 ) = 8x + 18\\\\x^2+x=8x+18\\\\x^2-7x-18=0\\\\x^2-9x+2x-18=0\\\\x(x-9)+2(x-9)=0\\\\x=-2 \  ,\ x = 9

Since, the numbers are positive so, x = -2 is ignored.

Therefore, the numbers are 9 and 10.

Hence, this is the required solution.

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Step-by-step explanation:

That should be it...

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wariber [46]

Given:

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Using sum of interior angles formula:

$S=(n-2) \times 180^{\circ}

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Divide by 180° on both sides.

$\frac{S}{180^{\circ}}=\frac{(n-2) \times 180^{\circ}}{180^{\circ}}

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adelina 88 [10]
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one of the students wants to make a tabletop shaped like a right triangle the tabletop will have the same area as the tabletop s
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Answer:

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