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frosja888 [35]
3 years ago
8

[(M^2N^2-MN)(M^2N^2+MN)]/MN

Mathematics
1 answer:
GaryK [48]3 years ago
3 0

Answer:

Step-by-step explanation:

M²N² - MN = MN (MN - 1)

M²N² + MN = MN (MN + 1)

\frac{(M^{2}N^{2}-MN)(M^{2}N^{2}-MN)}{MN}= \frac{MN(MN-1) * MN(MN + 1)}{MN}\\

                                     = (MN - 1) * MN * (MN + 1)

                                     = (MN - 1)(MN +1) MN             {(a+ b)(a - b) = a² - b² }

                                     = (M²N² - 1²) * MN

                                    = (M²N² - 1)MN

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