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frosja888 [35]
3 years ago
8

[(M^2N^2-MN)(M^2N^2+MN)]/MN

Mathematics
1 answer:
GaryK [48]3 years ago
3 0

Answer:

Step-by-step explanation:

M²N² - MN = MN (MN - 1)

M²N² + MN = MN (MN + 1)

\frac{(M^{2}N^{2}-MN)(M^{2}N^{2}-MN)}{MN}= \frac{MN(MN-1) * MN(MN + 1)}{MN}\\

                                     = (MN - 1) * MN * (MN + 1)

                                     = (MN - 1)(MN +1) MN             {(a+ b)(a - b) = a² - b² }

                                     = (M²N² - 1²) * MN

                                    = (M²N² - 1)MN

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Identify A, B, and C in the equation x - 3y + 4 = 0.
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Option D:

A = 1, B = –3 and C = 4.

Solution:

Given equation is x – 3y + 4 =0.

General equation of a line format:

<em>Ax + By + C = 0</em>

<u>To identify A, B and C in the given equation:</u>

x – 3y + 4 =0 is a equation of a line which is in the form of Ax + By + C = 0.

That is,

The coefficient of x is A ⇒ A = 1

The coefficient of y is B ⇒ B = –3

The constant term is C ⇒ C = 4

A = 1, B = –3 and C = 4.

Hence Option D is the correct answer.

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6 0
4 years ago
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1. Evaluate the function f(x)=3x-1 using the domain of -2, 0, 3, and 5. Results are to be shown in a table.
IceJOKER [234]

Answer:

See explanation

Step-by-step explanation:

You are given the function f(x)=3x-1

The domain of the function are all possible values of variable x, so you can find f(x) for x=-2, 0, 3, 5:

f(-2)=3\cdot (-2)-1=-6-1=-7\\ \\f(0)=3\cdot 0-1=0-1=-1\\ \\f(3)=3\cdot 3-1=9-1=8\\ \\f(5)=3\cdot 5-1=15-1=14

The table is

\begin{array}{cc}x&f(x)\\-2&-7\\0&-1\\3&8\\5&14\end{array}

The inverse function f^{-1}(x) has the domain which is the range of the function f(x) (all possible values of f(x)), so the domain of inverse function is {-7,-1,8,14}

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3 years ago
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