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3 years ago

How do you find the area of a triangle if you only know it's three sides?

1 answer:

8 0

You would have to find the height.

To do this, you cut the triangle from the upper vertex to the base to create two new triangles.

Then you use the Law of Cosines. You could use the google calculator for this by searching “law of cosines calculator” and inputting the values, but in case of a test, the formula is a^2 = b^2 + c^2 - 2bc cosA

If you could provide an example of a triangle, I will gladly help you with the steps! Hope this helped!

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Find an expression which represents the sum of (-8x+7y)(−8x+7y) and (2x-2y)(2x−2y) in simplest terms.

Yakvenalex [24]

Answer:

(-8x+7y)(−8x+7y)+(2x-2y)(2x−2y)= simplified - 68x^2+53y^2−120xy

I hope this helps ! <3

Step-by-step explanation:

3 0

3 years ago

Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B

Galina-37 [17]

Answer:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

$Min =120, Max= 150$

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

$Q_1 = \frac{140+120}{2}=130$

The median is the value in the 6th position from the dataset ordered and we got:

$Median= 135$

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

$Q_3 = \frac{140+143}{2}=141.5$

The five number summary for this case:

Min. 1st Qu. Median Mean 3rd Qu. Max.

120.0 130.0 135.0 135.6 141.5 150.0

The boxplot is on the figure attached

8 0

3 years ago

The area of the base of this prism is 35cm^2 , what is the volume of the prism

mr Goodwill [35]

V=Bh what is the height of the prism? You do (35^2 )(height)

3 0

3 years ago

Ms. Hamby gave a quiz. Two students' work and the answer key are shown. Ms. Hamby accepts equivalent answers in any form. Part A

Zina [86]

Answer:

attach a picture

Step-by-step explanation:

4 0

3 years ago

Find the center and the radius of the circle with the equation: x^2 +2x + y^2-2y-14 =0

FrozenT [24]

We need to convert the equation of the circle to standard form only then we can find the radius and the center of the circle.

$x^{2} +2x+ y^{2}-2y-14=0 \\ \\ 
x^{2} +2x+ y^{2}-2y=14 \\ \\ 
x^{2} +2(x)(1)+ y^{2}-2(y)(1)=14 \\ \\ 
 x^{2} +2x+1 + (y^{2}-2y+1)=14+1+1 \\ \\ 
(x+1)^{2}+(y-1)^{2} =16 
$

From this equation we can write:

Center of the circle is (-1,1) and the radius of the circle is 4.

5 0

3 years ago

Read 2 more answers