1) (2i-4)-(6i+9) = 2i-4-6i-9 = -4i-13
2) (-3+8i)+(3-8i) = -3+8i+3-8i = 0+0i = 0
Answer:
A
Step-by-step explanation:
expanding the bracket, we would have
-2x -18 = -x+1+2
-2x+x= 3 +18
-x=21
x=-21
Answer:
The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:
logb(a) = x ⇒ a = bˣ
So, for b = 0 ⇒ 0ˣ = a
And there is impossible, "a" only could be 0.
For b = 1 ⇒ 1ˣ = a
And the same thing would happen, the logarithming would be to be 1, and the function will be extremally restricted.
For b<0, then the expression a = bˣ will be also restricted, and will not represent all values of a.
So, 0<b<1 and b >1.
First you would subtract x from both sides to move all the x's to one side
Then you would add 4 to both side to move all the non x's to one side
Lastly divide by negative 15 to have x by itself
9/-15 =-.6
So x as has root at x=-0.6
