Answer:
1. A
2. D
3. D
Step-by-step explanation:
The standard form of a parabola is
..... (1)
Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.
1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .
...(a)
![(h,k+p)=(-2,-6)](https://tex.z-dn.net/?f=%28h%2Ck%2Bp%29%3D%28-2%2C-6%29)
.... (b)
![h=-2](https://tex.z-dn.net/?f=h%3D-2)
On solving (a) and (b), we get k=-7 and p=1.
Put h=-2, k=-7 and p=1 in equation (1).
![y=\frac{1}{4(1)}(x-(-2))^2+(-7)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%281%29%7D%28x-%28-2%29%29%5E2%2B%28-7%29)
![y=\frac{1}{4}(x+2)^2-7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%7D%28x%2B2%29%5E2-7)
Therefore option A is correct.
2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .
...(c)
![(h,k+p)=(2,1)](https://tex.z-dn.net/?f=%28h%2Ck%2Bp%29%3D%282%2C1%29)
.... (d)
![h=2](https://tex.z-dn.net/?f=h%3D2)
On solving (c) and (d), we get k=3 and p=-2.
Put h=2, k=3 and p=-2 in equation (1).
![y=\frac{1}{4(-2)}(x-(2))^2+(3)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%28-2%29%7D%28x-%282%29%29%5E2%2B%283%29)
![y=-\frac{1}{8}(x-2)^2+3](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B8%7D%28x-2%29%5E2%2B3)
Therefore option D is correct.
3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .
...(e)
![(h,k+p)=(0,-2)](https://tex.z-dn.net/?f=%28h%2Ck%2Bp%29%3D%280%2C-2%29)
.... (f)
![h=0](https://tex.z-dn.net/?f=h%3D0)
On solving (e) and (f), we get k=-2.5 and p=0.5.
Put h=0, k=-2.5 and p=0.5 in equation (1).
![y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%280.5%29%7D%28x-%280%29%29%5E2%2B%28-2.5%29)
![y=\frac{1}{2}(x)^2-2.5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7D%28x%29%5E2-2.5)
![y=\frac{1}{2}(x)^2-\frac{5}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B2%7D%28x%29%5E2-%5Cfrac%7B5%7D%7B2%7D)
Therefore option D is correct.