1st strategy: Add the first two terms and the last two.
16+35 + 24+14
51 + 38 = 89
2nd strategy: add the first and last term and the middle 2 terms.
16 + 35 + 24 + 14
30 + 59 = 89
584 is the total number of students in the school.
5/8 are in seventh grade and 3/8 are in eighth grade.
4/5 of the seventh graders participated in the track meet, so there were (4/5 · 5/8) · 584 students in the seventh grade participating in the track meet.
7/8 of the eighth graders participated, so there were (7/8 · 3/8) · 584 students in the eighth grade participating in the track meet.
So, all together, there were
(4/5 · 5/8) · 584 + (7/8 · 3/8) · 584 students from the school in the track meet.
Let's simplify as you asked:
(4/5 · 5/8) · 584 + (7/8 · 3/8) · 584 = [(4/5 · 5/8) + (7/8 · 3/8)] · 584 (distributive property - factoring)
= [20/40 + 21/64] · 584 (multiply fractions)
= (1/2 + 21/64) 584 (reduce the first fraction to lowest terms)
= (32/64 + 21/64) 584 (getting a common denominator)
= (53/64) 584 (combine/add the two fractions)
= 483.625 (multiply together)
All together, there were: 483.625 students in the meet.
Answer:
D
Step-by-step explanation:
6a-3b^2-a+b-4+7a^2
goup like terms
7a^2-3b^2+6a-a+b-4
7a^2-3b^+5a-4
Answer:
idk
Step-by-step explanation:
