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marysya [2.9K]
4 years ago
13

Is 3/5 greater or less than 1/4

Mathematics
2 answers:
JulsSmile [24]4 years ago
5 0
3/5 is greater than 1/4 and if u dont trust me then look at a graph
LenaWriter [7]4 years ago
5 0
3/5 is bigger than 1/4  for ex:

on a pie chart shade in 3/5 on one and 1/4 on the other. compare which has more shaded in

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What means lateral in math
Len [333]
Lateral surface area is the sum of all sides of a 3D object EXCEPT it's top and bottom bases.
7 0
4 years ago
Write the monomial in standard form. name it's coefficient and identify its degree.
Hunter-Best [27]

Answer:

Standard\ Form = {3n^2} m^{-2}

Step-by-step explanation:

Given

\frac{2}{3m^2n} * 4.5n^3

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

\frac{2}{3m^2n} * 4.5n^3

Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}

Split the numerator and the denominator

Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}

Multiply Like terms

Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}

Divide 9 by 3 to give 3

Standard\ Form = \frac{3 * n^3}{m^2 * n}

Divide n³ by n to n²

Standard\ Form = \frac{3 * n^2}{m^2 }

Split fraction

Standard\ Form = {3 * n^2} * \frac{1}{m^2 }

From laws of indices;

\frac{1}{a^n} = a^{-n}

Standard\ Form = {3 * n^2} * \frac{1}{m^2 } becomes

Standard\ Form = {3 * n^2} * m^{-2}

Multiply all together

Standard\ Form = {3n^2} m^{-2}

5 0
3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0
3 years ago
Can someone help me with this? It’s unit rates with price. Question: 6 feet of ribbon for $19.20​
lbvjy [14]

Answer:

OOPEEEEEEEEEEEEEEEE

Step-by-step explanation:

The answer is,

4.53

8 0
3 years ago
Read 2 more answers
50% of 30, hurry &lt;3<br> its saying my question is too short so ignore what im saying rn
9966 [12]

Answer:

The answer is 15

Step-by-step explanation:

50% of 30

30 × 50 ÷ 100 = 1500/100 = 15

Thus, The answer is 15

<u>-TheUnknownScientist</u><u> 72</u>

3 0
3 years ago
Read 2 more answers
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