> hello there stranger
Answer:
74676.
Step-by-step explanation:
Lets try multiplying 127 by 294 ( 127 is a prime number):
127 * 294 = 37338.
37338 / 196 = 190.5
37338 * 2 = 74676 which will now be divisible by 196.
74676 will be divisible by 98, 49 and 7 (because they are factors of 196).
It is also divisible by 84 ( to give 889) and therefore by 42, 28, 21, 14, 12, 6, 4, 3 , 2 and 1 which are all factors of 84.
Answer:
Infinity Many
Step-by-step explanation:
x can pretty much be any number possible. It will just equal something different every time.
Ok so to solve to first one u do this:
62.4 - 31.53, which gives u 30.87. and then u add 30.87 and 31.33, and u get 62.4
for the second one u do the same thing.
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)