Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
Answer:
We are given that a manufacturer sells a product as $2 per unit.
Quantity = q units
So, Total revenue = 
Total revenue = 
So, the total revenue function is
Marginal revenue is the derivative of the revenue functions
So, Marginal revenue = 
The marginal revenue function is 2
The constant marginal revenue function mean that the revenue earned by the addition of the output is constant.
Answer:
Step-by-step explanation:
If Amy started with 28 dollars and bought 7 pens, then had 20.30 dollars, we can subtract to find the price of all 7 pens.
28-20.30=7.70 dollars
now to find the amount for EACH pen, we divide by 7
7.70/7=1.1
each pen costed Amy 1 dollar and 10 cents with tax
Answer:
48 cupcakes were put on the plates.
Step-by-step explanation: 6 x 8 = 48
I hoped this answer helped you solve your problem!
Sincerely, iloveyouplease123ims
Answer:
<em>It will occur zero times between midnight and one o'clock.</em>
Step-by-step explanation:
<u>Least Common Multiple (LCM)</u>
Three events keep James from sleeping: his clock ticking every 20 seconds, a tap dripping every 15 seconds, and his dog snoring every 27 seconds.
All three events happened together at midnight. They will happen together again the first time the numbers 20, 15, and 27 have a common multiple. This is the LCM.
List the prime factors of each number:
20: 2,2,5
15: 3,5
27: 3,3,3
Now multiply all the factors the maximum number of times they appear:
LCM=2*2*3*3*3*5=540
(a) All the events will happen together again after 540 minutes.
(b) Since 540 minutes = 9 hours, this event won't happen again until 9 am. Thus, it will occur zero times between midnight and one o'clock.
