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3 years ago

Pls help due soon ty

Mathematics

2 answers:

Feliz [49]3 years ago

5 0

The first table : y=4x
the second table: y=1.5x
the third table: y= 1.25x

if you want help on how to do it: plug each of those equations into the “desmos” graph! from looking at those table points (x,y) you can find which equation matches the table

for instance on table one: I put y=4x into desmos then looked at graph one, I chose the point (2,8) I went to 2 on the x axis and moved my finger up 8 and that point was directly on the line meaning that table matches the equation. be sure to also do the same thing with the other points to double check!

My name is Ann [436]3 years ago

3 0

Answer:

The first table matches with the last equation.

The second table matches with the first equation.

The last table matches with the second equation.

Step-by-step explanation:

What I did was plug in the number in the x section for each table to see if the result of x times the number such as 4 resulted in the same number, y, that was paired with the x number based on the table.

Ex: Using table 1,

y=4x

y=4(2) --> I substituted the x for row 1 x in table 1

y=8

Check:

The first table shows that for row 1, the y was 8 so our match was correct.

Hope this helps!

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This is gonna be the death of me

kykrilka [37]

Hey!
So you have a net of the figure. It's broken into several 2D shapes. What you an do it find the area of each shape and add it together.
Triangles:
A = (b*h)/2
A= (5 * 3) / 2
A = 15/2
same thing for the second one
15/2 * 2 = 15
Don't forget, there are 2 triangles so it's really 15 for both

Rectangles:
A=b*h
A= 7*5
A=35

A=7*5
A=35

A=3*7
A=21

35+35+21=91

Now add the sum of the area of the triangles and the sum of the area of the rectangles

91+15 = 106

106 is the surface area
Hope this helps!

5 0

2 years ago

A business owner opens one store in town A. The equation p(x) = 10,000(1.075) represents the anticipated profit after t years. T

alexgriva [62]

The rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t

So, given that both store A and store B follow the same equations but t is different for them, you can right:

Store A: pA (t) 10,000 (1.075)^t

Store B: pB(t'): 10,000 (1.075)^t'

=> pA(t) / pB(t') = 1.075^t / 1.075^t'

=> pA(t) / pB(t') = 1.075 ^ (t - t')

And t - t' = 0.5 years

=> pA(t) / pB(t') = 1.075 ^ (0.5) = 1.0368

or pB(t') / pA(t) = 1.075^(-0.5) = 0.964

=> pB(t') ≈ 0.96 * pA(t)

Which means that the profit of the store B is about 96% the profit of store A at any time after both stores have opened.

7 0

2 years ago

Read 2 more answers

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

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2 years ago

Factor completely

svet-max [94.6K]

Answer:

B.) 2(5x-4)(x+1)

Step-by-step explanation:

10x^2+2x-8

= 2(5x^2 + x - 4)

= 2(5x^2 + 5x - 4x - 4)

= 2[5x(x + 1) - 4(x + 1)]

= 2(5x-4)(x+1)

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3 years ago

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Cp ps unit 8A: Motion distance and displacement lab activity

bazaltina [42]

The difference from distance and displacement is <u>the direction</u>

<h3>Further explanation</h3>

Distance is a scalar quantity that indicates the length of the trajectory that is traveled by an object within a certain interval. Distance has no direction, only has magnitude

Can be simplified distance = total meters traveled

displacement is a vector quantity that shows changes in the position of objects in a certain interval of time. Displacement has magnitude and direction

Can be simplified displacement = distanced traveled from starting point to ending point

Some examples of distanced and displacement

1. first move: move 4 meters north

second move: move 2 meters south

Distanced: 6 meters

Displacement: 2 meters north

2. first move: move 2 meters east

second move: move 4 meters west

Distanced: 6 meters

Displacement: 2 meters west

etc

<h3>Learn more</h3>

uniformly accelerated motion

brainly.com/question/13750982

Keywords: distance and displacement lab activity

#LearnwithBrainly

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2 years ago