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3 years ago

Can you evaluate an expression?

Mathematics

2 answers:

ozzi3 years ago

8 0

Yes you can just write down how you feelabout something that'll help alot

Tresset [83]3 years ago

8 0

Yes you can evaluate an expression by<span> that you have to substitute a number for each variable and perform the arithmetic operations.</span>

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50 POINT GIVEAWAY AND BRAINLEST FOR the FIRST ANSWER

Zina [86]

Answer:

thank you

Step-by-step explanation:

8 0

2 years ago

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What is the slope of a line perpendicular to the line y=-1/4x-1

ella [17]

-1/4
I really hope this helps

4 0

3 years ago

Victoria and Georgetown are 67.2 miles from each other. How far apart would the cities be on a map that has a scale of 0.9 inche

Artemon [7]

Answer: 5.76 miles

Step-by-step explanation:

Let the distance between Victoria and Georgetown on the map be represented by x.

The information given in the question can then be formed into an expression which will be:

0.9/x = 10.5/67.2

Cross multiply

(10.5 × x) = 67.2 × 0.9

10.5x = 60.48

x = 60.48/10.5

x = 5.76

The answer is 5.76 miles

7 0

3 years ago

The equation y = 0.25x describes a proportional relationship between x and y. What is the constant of proportionality?

hoa [83]

Answer:

k = 0.25

Step-by-step explanation:

The standard equation of a proportional relationship is

y = kx ← k is the constant of proportion

y = 0.25x ← is in this form

with k = 0.25

8 0

3 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

4 0

3 years ago