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ryzh [129]
3 years ago
8

Can you evaluate an expression?

Mathematics
2 answers:
ozzi3 years ago
8 0
Yes you can just write down how you feelabout something that'll help alot
Tresset [83]3 years ago
8 0
Yes you can evaluate an expression by<span> that you have to substitute a number for each variable and perform the arithmetic operations.</span>
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50 POINT GIVEAWAY AND BRAINLEST FOR the FIRST ANSWER
Zina [86]

Answer:

thank you

Step-by-step explanation:

8 0
2 years ago
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What is the slope of a line perpendicular to the line y=-1/4x-1
ella [17]
-1/4
I really hope this helps
4 0
3 years ago
Victoria and Georgetown are 67.2 miles from each other. How far apart would the cities be on a map that has a scale of 0.9 inche
Artemon [7]

Answer: 5.76 miles

Step-by-step explanation:

Let the distance between Victoria and Georgetown on the map be represented by x.

The information given in the question can then be formed into an expression which will be:

0.9/x = 10.5/67.2

Cross multiply

(10.5 × x) = 67.2 × 0.9

10.5x = 60.48

x = 60.48/10.5

x = 5.76

The answer is 5.76 miles

7 0
3 years ago
The equation y = 0.25x describes a proportional relationship between x and y. What is the constant of proportionality?
hoa [83]

Answer:

k = 0.25

Step-by-step explanation:

The standard equation of a proportional relationship is

y = kx ← k is the constant of proportion

y = 0.25x ← is in this form

with k = 0.25

8 0
3 years ago
Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th
xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

P:(x - 1)^2 + (y + 6)^2 = 9

Q:(x + 4)^2 + (y + 14)^2 = 4

Solving (a): The distance between both

The equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

Where

Center: (h,k)

Radius:r

P and Q can be rewritten as:

P:(x - 1)^2 + (y + 6)^2 = 3^2

Q:(x + 4)^2 + (y + 14)^2 = 2^2

So, for P:

Center = (1,-6)

r = 3

For Q:

Center = (-4,-14)

r = 2

The distance between them is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

Where:

Center = (1,-6) --- (x_1,y_1)

Center = (-4,-14) --- (x_2,y_2)

So:

d = \sqrt{(1 - -4)^2 + (-6 - -14)^2

d = \sqrt{(5)^2 + (8)^2

d = \sqrt{25 + 64

d = \sqrt{89

d = 9.4

Solving (b): The radius;

In (a), we have:

r = 3 --- circle P

r = 2 --- circle Q

By comparison

2 < 3

<em>Hence, circle Q has a smaller radius</em>

4 0
3 years ago
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