This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:
T-intercept = 67
Step-by-step explanation:
Given
T = 44m + 67
Required
Calculate and interpret the t-intercept
To calculate the t-intercept, we simply set the number of minutes (m) to 0
i.e. substitute 0 for m in T = 44m + 67
T = 44 * 0 + 67
T = 0 + 67
T = 67
Hence, the T-intercept is 67
The interpretation is that the initial temperature when the oven is turned on is 67 degrees
Yes this is correct because that angle in is with the other angles to
No. of people don't like to be teacher
= 100% - 75% = 25%
<h3>

</h3>
So, 15 number of students doesn't like to be teacher
Answer:
X=40°
X=30°
X=50°
Step-by-step explanation:
Let our unknown angles be denoted by 
Part I
We are given the sum of the angles as 70°, the known as 30° and the unknown as X;
To find X, we subtract the known angle from the sum as:
X=70°-30°=40°
Hence X= 40°
Part II
We are given the sum of the angles as 70°, the known as 40° and the unknown as X;
To find X, we subtract the known angle from the sum as:
X=70°-40°=30°
Hence X= 30°
Part III
We are given the sum of the angles as 80°, the known as 30° and the unknown as X;
To find X, we subtract the known angle from the sum as:
X=80°-30°=50°
Hence X= 50°