Question

Triangle AOC intersects a circle with center O. side AO is 10 inches and the diameter of the circle is 12 inches. What is the length of BC

Answer 1

Answer:

$AC=8inches$

Step-by-step explanation:

It is given that triangle AOC intersects a circle with center O, side AO is 10 inches and the diameter of the circle is 12 inches, thus

OC is the radius of the circle and is equal to $\frac{D}{2}=\frac{12}{2}=6 inches$.

Now, From ΔAOC, using the Pythagoras theorem, we get

$(OA)^{2}=(OC)^{2}+(AC)^{2}$

⇒$(10)^{2}=(6)^2+(AC)^2$

⇒$100=36+(AC)^2$

⇒$64=(AC)^2$

⇒$AC=8inches$