Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
The thesis statement is typically located in the last sentence of the first paragraph of a research paper.
The Answer is toolbar.
<span>The mini or small toolbar contains frequently used formatting commands that are displayed when selecting text or objects with the mouse.
Toolbar is also known as Ribbon. It is present in computer interface design. We can see toolbar in many softwares like Microsoft office suite, web explorer, designing softwares etc. it is mostly present under the menu bar and it has many options.</span>
Answer:
Offer second chances/clean slates.
Be resourceful.
Make learning active.
Be an advocate.
Pursue lifelong learning.
Answer:
I. The class methods and instance methods of one class may call the public class methods of another class using dot notation and referencing the name of the other class.
Explanation:
Private methods are being accessed from only within the class or scope specified. No other means of accessibility is possible, and even through inheritance. And instance methods can never call without using dot notation, any of the class method of the same class. Hence second and third options are not correct. And the class method and the instance methods of one class may call the public class methods of another class using the dot notation and referencing the name of the other class. Hence, the correct option is the first one.
