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OLEGan [10]
2 years ago
9

Find the largest prime divisor of $15^6 - 7^6$

415%5E6%20-%207%5E6%24" id="TexFormula1" title="Find the largest prime divisor of $15^6 - 7^6$" alt="Find the largest prime divisor of $15^6 - 7^6$" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Novosadov [1.4K]2 years ago
7 0

Answer:

Largest prime factor of the given expression is <em>379.</em>

Step-by-step explanation:

Given the expression:

15^6 - 7^6

To find:

The largest prime factor of the given expression.

Solution:

First of all, let us factorize the given expression.

15^6 - 7^6\\\Rightarrow (15^3)^2 - (7^3)^2\\\\\text{Using } x^{2} -y^2 = (x+y) (x-y)\\\\\Rightarrow (15^3+7^3)(15^3-7^3)

Let us learn two formula:

x^3+y^3 = (x+y)(x^2+y^2-xy)

x^3-y^3 = (x-y)(x^2+y^2+xy)

Applying the above formula in the expression written above:

(15^3+7^3) = (15+7)(15^2+7^2-15\times 7)\\\Rightarrow 22(225+49-105 ) = 2 \times 11 \times 169 \\\Rightarrow 2 \times 11\times 13\times 13\\\Rightarrow 2 \times 11\times 13^2 ...... (1)

Similarly:

(15^3-7^3) = (15-7)(15^2+7^2+15\times 7)\\\Rightarrow 8(225+49+105 ) = 2^3 \times 379........ (2)

Multiplying the expressions from (1) and (2) to get the result:

\therefore 15^6 - 7^6 = 2^4 \times 11 \times \underline{\bold{379}} \times 13 ^2

So, largest prime factor of the given expression is <em>379.</em>

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Answer:

1

Step-by-step explanation:

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2 years ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
A television screen, length is 16 1/2 inches, width is w inches, and area is 462 square inches. Select all THREE equations that
tatiyna

Answer:

it's B, C, and D

Step-by-step explanation:

A. w ⋅ 462 = 16 1/2

not A

w * a ≠ l

B. 16 1/2 ⋅ w = 462

is B

l * w = a

C. 462 ÷ 16 1/2 = w

is C

a / l = w

D. 462 ÷ w = 16 1/2

is D

a / w = l

E. 16 1/2 ⋅ 462 = w

not E

l * a ≠ w

3 0
2 years ago
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Answer:

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Step-by-step explanation:

y=\frac{1}{2}x-3

Slope of this line m₁ = 1/2

Slope of the line perpendicular to this line = m₂

m₁ *m₂ = -1

m₂ = -1 *2/1 = -2

Slope  = -2; (1,3)

y- y₁ = m(x-x₁)

y - 3 = -2(x - 1)

y - 3 = -2x + 2

y = -2x +2 +3

y = -2x + 5

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telo118 [61]

Answer:3


Step-by-step explanation:


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