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Oduvanchick [21]
3 years ago
15

1 Factorise completely. (a) 2a+4+ap+2p (b) 162 – 8t^2

Mathematics
2 answers:
Rasek [7]3 years ago
7 0

Step-by-step explanation:

a. 2a + 4 + ap + 2p

2a + ap + 4 + 2p

a (2 + p) + 2 (2 + p)

= ( a + 2) ( 2 + p)

b. 162 - 8t^2

2( -4t^2 + 81)

user100 [1]3 years ago
4 0

Answer:

Step-by-step explanation:

a) 2a + 4 + ap + 2p = <u>2*a + 2*2</u> + <u>a *p + 2*p</u>

                               = 2(a + 2) + p(a + 2)

                              =  (a +2) (2 + p)

b) 162 - 8t² = 2*81 - 2*4t²

                 = 2 (81  - 4t²)

                = 2( 9² - (2t)² )          {a² - b² = (a + b)(a -b)

                = 2 ( 9 + 2t) (9 - 2t)

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Read 2 more answers
2. Solve the equation by completing the square. Show your work.
scoundrel [369]

Answer:

<u>x = 5 or 25</u>

Step-by-step explanation:

I think the method I am about to explain is slightly quicker and easier than the method in your question. This works for any 'complete the square' question.

We begin with x² - 30x = - 125.

First, we are going to factorise the left-hand side of the equation by <u>dividing the 'b' value </u><u>(-30)</u><u> by 2</u> (you'll see why this works in a minute):

(x - 15)²

We want these brackets to multiply out to give x² - 30x, so that they equal the left-hand side of the equation. Unfortunately, if we multiply them out, we get:

(x - 15)(x - 15) =

<u>x² - 30x + 225</u>

There is an <u>unwanted term</u> (the + 225, from 15²)! We only want x² - 30x, so we have to remove this term by <u>subtracting it from the left side of the equation</u>. To do this, let's set up the original equation again:

(x² - 30x + 225) <u>- 225</u> = - 125

<em>Note: </em><em>The reason why we don't have to subtract it from both sides is because the original equation is </em><em>x² - 30x = - 125</em><em>, and so we must make sure the left hand side is still equal to </em><em>x² - 30x</em><em>.</em>

So now we know that (x - 15)² multiplies out to give x² - 30x +225, we can write this as (x - 15)² in our equation:

(x² - 30x + 225) - 225 = - 125

is the same as:

(x - 15)² - 225 = - 125

Now add 225 to <u>both sides</u> of the equation:

(x - 15)² = - 125 + 225 = 100

(x -15)² = 100

The next step is to square root both sides. Be careful here, and remember that √100 can either be 10 or -10, as (-10)² = 100. To indicate both results, write ±10 ("plus or minus 10").

√(x - 15)² = √100

x - 15 = ±10

Because, there are two possible values for the right-hand side of the equation, we need to separate our equation into two equations:

1.     x - 15 = 10

and

2.    x - 15 = -10

Now we solve these two simple linear equations for x:

1.     x = 10 + 15   <- add 15 to both sides

        <u>x = 25</u> This is our first solution.

2.    x = -10 + 15  <- add 15 to both sides again

        <u>x = 5</u> This is our other solution.

<u>So our two solutions are x = 5 and x = 25!</u>

I have attached the quick version of the working out for this question - that is what you would be expected to write down in a test.

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Answer:

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Choice B contradicts the previous statement.

Choice C is wrong because the x-intercept is the zero of the function. This is because at a given x-coordinate that touches the x-axis, the y-coordinate will be 'zero'.

Choice D is wrong because the y-intercept is where x = 0.

I hope this helps!

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Step-by-step explanation:

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