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1 year ago

Five hundred ten of 650 high school students said that pizza was their favorite food in the school cafeteria.

Mathematics

1 answer:

ICE Princess25 [194]1 year ago

7 0

If Five hundred ten of 650 high school students said that pizza was their favorite food. The margin of error is 0.0322.

<h3>Margin of error</h3>

Given:

Sample proportion=Five hundred ten=510

Sample size=650

Hence:

Margin of error=z×√p×(1-p)/n

Margin of error=2√510/650× (1-510/650)÷650

Margin of error=2√0.78461538×(1-0.78461538)÷650

Margin of error=2√0.78461538×0.21538462÷650

Margin of error=2√0.168994085÷650

Margin of error=2√0.0002599909

Margin of error=0.0322

Therefore the correct option is D.

Learn more about margin of error here:brainly.com/question/24289590

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A recent survey of 128 high school students indicated the following information about release times from school. -35 percent wan

wlad13 [49]

Answer:

The interval is for those that want to get out earlier is between 43 student to 47 students

The interval is for those that want to get out later is between 48 student to 50 students

Step-by-step explanation:

Given that:

sample size n=128

Probability of those that want to get out earlier = 0.35.

The mean = n × probability = 0.35 × 128 = 44.8 ≈ 45

Margin of error = 4% = 0.04 × 44.8 = 1.79 ≈ 2

Therefore the interval = mean ± Margin of error = 45 ± 2 = (43, 47)

The interval is for those that want to get out earlier is between 43 student to 47 students

Probability of those that want to get out later = 0.39.

The mean = n × probability = 0.39 × 128 = 49.92 ≈ 50

Margin of error = 4% = 0.04 × 50 = 2

Therefore the interval = mean ± Margin of error = 50 ± 2 = (48, 52)

The interval is for those that want to get out later is between 48 student to 50 students

the group that wants to get out of school earlier to win after all the votes are counted if those that have no opinion decide that they want to go earlier

5 0

3 years ago

A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On

uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$