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3 years ago

I have $3.35 in quarters and dimes. if i have 23 coins in all, find the number of quarters and dimes

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

16 dimes and 7 quarters
I hope this helps :)

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I'm having a very hard time with geometry and was hoping someone could help me, sorry i know this isn't exactly a question

natulia [17]

Answer:

What kind of geometry EX. 6th grade 7th grade 8th grade Eureka etc.

Step-by-step explanation:

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3 years ago

A college student completed some courses worth 3 credits and some courses worth 4 credits. The student earned a total of 59 cred

DedPeter [7]

Answer:

They completed 13, 3 credit classes

Step-by-step explanation:

1. Make 2 formulas. In this case: x+y=18

and 3x+4y=59

2. Then multiply x+y=18 by 3 and subtract the two equations.

Find y which is 5 and input into the equations. Then find your answer.

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3 years ago

HURRY, I NEED AN ANSWER<br><br> (-0.3)(-0.27)

leva [86]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

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3 years ago

Choose the type of variation that relates the variables in the table.

Ronch [10]

Answer:

Multiply the x by 5 to get the y

5 0

2 years ago