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MArishka [77]
3 years ago
13

Sqr of 10(-3sqr 2-2sqr 5)

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0
\sqrt{10(-3sqr^{2} - 2sqr^{5}} \\\sqrt{10(-3sqr^{2}) - 10(2sqr^{5})} \\\sqrt{-30sqr^{2} - 20sqr^{5}} \\\sqrt{(r^{2} * (-1) * 30sq) - (4r^{4} * 5sqr)} \\r^{2}i - 2r^{2}\sqrt{30sq - 5sqr
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What is an equation of the line that passes through the points (2, -7) and (8, -4)?
Virty [35]

Answer:

The answer is

<h2>y =  \frac{1}{2} x - 8</h2>

Step-by-step explanation:

To find the equation of the line that passes through two points , first find the slope and then use the formula

y - y1 = m(x - x1)

where m is the slope

(x1 , y1) are any of the points

To find the slope of the line using two points we use the formula

m =  \frac{y2 - y1}{x2 - x1}

Slope of the line using points

(2, -7) and (8, -4) is

<h3>\frac{ - 4 + 7}{8 - 2}  =  \frac{3}{6}  =  \frac{1}{2}</h3>

Now the equation of the line using point (2 , - 7) and slope 1/2 is

<h3 /><h3>y + 7 =  \frac{1}{2} (x - 2)</h3><h3 /><h3>y + 7 =  \frac{1}{2} x - 1</h3><h3>y =  \frac{1}{2} x - 1 - 7</h3><h3 />

We have the final answer as

<h3>y =  \frac{1}{2} x - 8</h3>

Hope this helps you

6 0
4 years ago
Rectangle ABCD is rotated about the origin to form rectangle A'B'C'D'. The perimeter of ABCD is 16 units.
Studentka2010 [4]

Answer:

16units

Step-by-step explanation:

It was only rotated. It's area and perimeter stay the same.

5 0
3 years ago
Read 2 more answers
Which of the following properties describes the mathematical expression?
schepotkina [342]

Answer:

Identity

Step-by-step explanation:

7+2=2+7

is an identity

7 0
3 years ago
How do you solve 4x+1/3=x-5/2
Lemur [1.5K]
4x+1/3=x-5/2
4x-x=-5/2-1/3
3x=-17/6
1/3(3x)=1/3(-17/6)
X=-17/18
5 0
3 years ago
If BC = 4.5, CD = 7.7, and AD = 16.7, find AB to the nearest tenth.
Elodia [21]
We are already given with the following
BC = 4.5
CD = 7.7
AD = 16.7
We are asked for AB
Assuming that the line segments are colinear, we have the equation
AB + BC + CD = AD
Substituting
AB + 4.5 + 7.7 = 16.7
AB = 4.5
5 0
3 years ago
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