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kondor19780726 [428]
2 years ago
6

If BC = 4.5, CD = 7.7, and AD = 16.7, find AB to the nearest tenth.

Mathematics
1 answer:
Elodia [21]2 years ago
5 0
We are already given with the following
BC = 4.5
CD = 7.7
AD = 16.7
We are asked for AB
Assuming that the line segments are colinear, we have the equation
AB + BC + CD = AD
Substituting
AB + 4.5 + 7.7 = 16.7
AB = 4.5
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If 5-y^2=x^2 then find d^2y/dx^2 at the point (2, 1) in simplest form. ​
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Answer:

y"(2, 1) = -5

Step-by-step explanation:

Step 1: Define implicit differentiation

5 - y² = x²

Step 2: Find dy/dx

  1. Take implicit differentiation: -2yy' = 2x
  2. Isolate y': y' = 2x/-2y
  3. Isolate y': y' = -x/y

Step 3: Find d²y/dx²

  1. Quotient Rule: y'' = [y(-1) - y'(-x)] / y²
  2. Substitute y': y" = [-y - (-x/y)(-x)] / y²
  3. Simplify: y" = [-y - x²/y] / y²
  4. Multiply top/bottom by y: y" = (-y² - x²) / y³
  5. Factor negative: y" = -(y² + x²) / y³

Step 4: Substitute and Evaluate

y"(2, 1) = -(1² + 2²) / 1³

y"(2, 1) = -(1 + 4) / 1

y"(2, 1) = -5/1

y"(2, 1) = -5

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2 years ago
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Answer:3.14r^2

Step-by-step explanation:

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