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3 years ago

Match the angle measures with the value of x in each triangle. i!mages below!

Mathematics

1 answer:

Katena32 [7]3 years ago

3 0

Step-by-step explanation:

left side X°=33(i.e 75+72+x=180)

left side down x°= 60°

right side=145°

right side down= 124

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5<br> Find the slope of a line parallel to 2y - 6x+8.<br> -6

morpeh [17]

Answer:

Change the equation to the slope intercept form (y = mx + b)

2y = 6x + 8

Divide equation by 2

y = 3x + 4

Therefore

The line as a y intercept of 4

Parallel lines have the same slope;

Find the slope by putting in the equation in the point/intercept form

4x + 4y = 20

4y = -4x + 20

Divide equation by 4, results

y = -1x + 5

Now we know the slope (-1) and the y intercept (+4) if the line

y = -1x + 4

or just

y = -x + 4 is "the line"

Step-by-step explanation:

5 0

3 years ago

7 - 2x = 11<br> What is the value of x? Show your working.

sukhopar [10]

Answer: x = - 4

Step-by-step explanation:

7-2x=1

PEMDAS

so add 7 to both sides

-2x=8

divide by -2 from both sides

x=-4

8 0

2 years ago

Read 2 more answers

Examination, 152 Candidates offered Agriculture

agasfer [191]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the given details

$n(G)=136,n(P)=128,n(A)=152,n(A\cap G)=52,n(A\cap P)=60,n(A\cap P\cap G)=30,n(P\cap G)=58$

STEP 2: Get the number of students that takes the subjects only

From the basic stuff, we have Number of candidates who had taken only each of the subjects

$\begin{gathered} n(A\text{ only)=}n(A)-\lbrack n(A\cap P)+n(A\cap G)-n(A\cap P\cap G)_{}\rbrack \\ \Rightarrow152-\lbrack52+60-30\rbrack=152-82=70 \\ \\ n(G\text{ only)=}n(G)-\lbrack n(A\cap G)+n(P\cap G)-n(A\cap P\cap G)\rbrack \\ \Rightarrow136-\lbrack52+58-30\rbrack=56 \\ \\ n(P\text{ only)=}128-\lbrack58+60-30\rbrack=40 \end{gathered}$

STEP 3: Represent the values above on a Venn Diagram after getting the values

STEP 4: Find the total number of candidate that sat for the exam.

$\begin{gathered} We\text{ su}m\text{ all the numbers in the Venn diagram to get the total number of candidates that sat for the exam} \\ We\text{ have:} \\ 70+22+30+30+28+56+40=276 \end{gathered}$

Hence, the total number of candidates that sat for the exam is 276