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AysviL [449]
3 years ago
5

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

s below. What was Jada’s error?
Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction
Negative StartFraction 4 over 9 EndFraction (Negative StartFraction 9 over 4 EndFraction) = StartFraction x over 108 EndFraction (Negative StartFraction 9 over 4 EndFraction)
x = negative StartFraction 1 over 48 EndFraction

Jada should have multiplied both sides of the equation by 108.
Jada should have multiplied both sides of the equation by Negative StartFraction 4 over 9 EndFraction.
The product of Negative StartFraction 9 over 4 EndFraction and StartFraction 1 over 108 EndFraction is not equal to Negative StartFraction 1 over 48 EndFraction.
The product of Negative StartFraction 9 over 4 EndFraction and 108 should have been the value of x.
Mathematics
2 answers:
netineya [11]3 years ago
8 0

Answer:

A

Step-by-step explanation:

navik [9.2K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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Find the product ( x ≠ ? )
dsp73

Answer:

-3

Step-by-step explanation:

if x= -3

the denominator becomes 0 and the fraction becomes undefined.

8 0
3 years ago
Gas is escaping from a spherical balloon at the rate of 12 ft3/hr. At what rate (in feet per hour) is the radius of the balloon
bija089 [108]

Answer:

This is the rate at which the radius of the balloon is changing when the volume is 300 ft^3 \frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \:\frac{ft}{h}  \approx -0.05537 \:\frac{ft}{h}

Step-by-step explanation:

Let r be the radius and V the volume.

We know that the gas is escaping from a spherical balloon at the rate of \frac{dV}{dt}=-12\:\frac{ft^3}{h} because the volume is decreasing, and we want to find \frac{dr}{dt}

The two variables are related by the equation

V=\frac{4}{3}\pi r^3

taking the derivative of the equation, we get

\frac{d}{dt}V=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4}{3}\pi (3r^2)\frac{dr}{dt} \\\\\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}

With the help of the formula for the volume of a sphere and the information given, we find r  

V=\frac{4}{3}\pi r^3\\\\300=\frac{4}{3}\pi r^3\\\\r^3=\frac{225}{\pi }\\\\r=\sqrt[3]{\frac{225}{\pi }}

Substitute the values we know and solve for \frac{dr}{dt}

\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=-\frac{12}{4\pi (\sqrt[3]{\frac{225}{\pi }})^2} \\\\\frac{dr}{dt}=-\frac{3}{\pi \left(\sqrt[3]{\frac{225}{\pi }}\right)^2}\\\\\frac{dr}{dt}=-\frac{3}{\pi \frac{225^{\frac{2}{3}}}{\pi ^{\frac{2}{3}}}}\\\\\frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \approx -0.05537 \:\frac{ft}{h}

7 0
4 years ago
(3/4 - 1/5) ÷ (5/2 - 1/3) xfa ayuda con procedimiento rapido​
GuDViN [60]

Answer:

33/130

Step-by-step explanation:

3/4 - 1/5 = 11/20

5/2 - 1/3 = 2 and 1/6

11/20 divided by 13/6 = 33/130

8 0
3 years ago
3) A chef randomly chooses subscription information from his blog readers to determine people who are likely to watch his new co
frosja888 [35]

Answer:

The answer is D, the random sample does not represent all people who are likely to watch the chef's cooking show.

Step-by-step explanation:

This is because not all people who enjoy cooking know about or visit the chef's blog.

7 0
3 years ago
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The approximate value of 4 times 10 Superscript 9 divided by left parenthesis 1.5 times 10 Superscript 6 right parenthesis is
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